Category: Mechanics

Question Number 105807 by aurpeyz last updated on 31/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 40166 by ajfour last updated on 16/Jul/18 Answered by MrW3 last updated on 17/Jul/18 $${a}={acceleration}\:{of}\:{m}\:\left(\uparrow\right) \\ $$$${A}={acceleration}\:{of}\:{M}_{\mathrm{0}} \:\left(\rightarrow\right) \\ $$$${a}_{\mathrm{1}} ={acceleration}\:{of}\:{M}\:\left(\swarrow\right)\:{on}\:{M}_{\mathrm{0}} \\ $$$${with}\:{a}_{\mathrm{1}}…

Question Number 40058 by rahul 19 last updated on 15/Jul/18 Answered by rahul 19 last updated on 16/Jul/18 $$\mathrm{By}\:\mathrm{Energy}\:\mathrm{conservation} \\ $$$$\mathrm{10}.\mathrm{10}.\mathrm{3}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\:.\mathrm{100}.\left(\mathrm{1}\right)^{\mathrm{2}} \:=\:\frac{\mathrm{1}}{\mathrm{2}}.\:\mathrm{10}.\mathrm{v}^{\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{v}=\:\sqrt{\mathrm{70}}\:\mathrm{m}/\mathrm{s} \\…

Question Number 40012 by rahul 19 last updated on 15/Jul/18 Answered by ajfour last updated on 15/Jul/18 $$\left({mg}\right)_{{max}} =\frac{\mathrm{3}{Mg}}{\mathrm{5}}+\frac{\mathrm{0}.\mathrm{6}\left(\mathrm{4}{Mg}\right)}{\mathrm{5}} \\ $$$$\:\:\:\:\Rightarrow\:{m}_{{max}} =\mathrm{30}{kg}+\mathrm{24}{kg}\:=\:\mathrm{54}{kg} \\ $$$$\left({mg}\right)_{{min}} =\frac{\mathrm{3}{Mg}}{\mathrm{5}}−\frac{\mathrm{0}.\mathrm{6}\left(\mathrm{4}{Mg}\right)}{\mathrm{5}}…

Question Number 105476 by ajfour last updated on 29/Jul/20 Commented by ajfour last updated on 29/Jul/20 $${Find}\:{the}\:{mass}\:{of}\:{the}\:{square}\:{plate} \\ $$$${OABC},\:{if}\:{mass}\:{density}\:{per}\:{unit} \\ $$$${area}\:{is}\:{proportional}\:{to}\:{the} \\ $$$${distance}\:{from}\:{corner}\:{O},\:\:{given} \\ $$$${by}\:\:\boldsymbol{\rho}=\boldsymbol{{kr}}/\boldsymbol{{a}}.…