Question Number 105838 by aurpeyz last updated on 01/Aug/20 $${A}\:{mass}\:{of}\:\mathrm{1}.\mathrm{5}{kg}\:{out}\:{in}\:{space}\:{moves}\:{in}\: \\ $$$${a}\:{circle}\:{of}\:{radius}\:\mathrm{25}{cm}\:{at}\:{a}\:{constant}\:\mathrm{2}{rev}/{s}. \\ $$$${Calculate}\:\left({a}\right)\:{the}\:{tangential}\:{speed}\: \\ $$$$\left({b}\right)\:{acceleration}\:{and}\:\left({c}\right)\:{the}\:{required}\: \\ $$$${centripetal}\:{force}\:{for}\:{the}\:{motion}. \\ $$ Terms of Service Privacy Policy…
Question Number 105840 by aurpeyz last updated on 01/Aug/20 $${A}\:{Car}\:{wheel}\:\mathrm{30}{cm}\:{in}\:{radius}\:{is}\:{turning}\:{at}\:{a} \\ $$$${rate}\:{of}\:\mathrm{8}{rev}/{s}\:{when}\:{the}\:{car}\:{begins}\:{to}\:{slow}\:\: \\ $$$${uniformly}\:{to}\:{rest}\:{in}\:{a}\:{time}\:\mathrm{14}{s}.\:{find}\:{the}\: \\ $$$${number}\:{of}\:{revolutions}\:{made}\:{by}\:{the}\:{wheel} \\ $$$${and}\:{the}\:{distance}\:{the}\:{car}\:{goes}\:{in}\:{the}\:\mathrm{14}{s}. \\ $$ Terms of Service Privacy Policy…
Question Number 105839 by aurpeyz last updated on 01/Aug/20 $${A}\:{wheel}\:\mathrm{25}{cm}\:{in}\:{a}\:{radius}\:{turning}\:{at}\:\mathrm{120}{rpm} \\ $$$${un}\mathrm{i}{formly}\:{increases}\:{its}\:{frequency}\:{to}\:\mathrm{660}{rpm} \\ $$$${in}\:\mathrm{9}{s}.\:{Find}\:\left({a}\right)\:{the}\:{constant}\:{angular}\: \\ $$$${acceleration}\:{in}\:{rad}/{s}^{\mathrm{2}} \:{and}\:\left({b}\right)\:{tangential} \\ $$$${acceleration}\:{of}\:{a}\:{point}\:{on}\:{its}\:{rim}. \\ $$ Terms of Service Privacy…
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Question Number 40166 by ajfour last updated on 16/Jul/18 Answered by MrW3 last updated on 17/Jul/18 $${a}={acceleration}\:{of}\:{m}\:\left(\uparrow\right) \\ $$$${A}={acceleration}\:{of}\:{M}_{\mathrm{0}} \:\left(\rightarrow\right) \\ $$$${a}_{\mathrm{1}} ={acceleration}\:{of}\:{M}\:\left(\swarrow\right)\:{on}\:{M}_{\mathrm{0}} \\ $$$${with}\:{a}_{\mathrm{1}}…
Question Number 105594 by ajfour last updated on 30/Jul/20 Commented by ajfour last updated on 30/Jul/20 $${Find}\:{maximum}\:\boldsymbol{{x}},\:{for}\:{y}>\mathrm{0}. \\ $$$${The}\:{two}\:{cylinders}\:{have}\:{radii}\:\boldsymbol{{r}}. \\ $$ Commented by ajfour last…
Question Number 40058 by rahul 19 last updated on 15/Jul/18 Answered by rahul 19 last updated on 16/Jul/18 $$\mathrm{By}\:\mathrm{Energy}\:\mathrm{conservation} \\ $$$$\mathrm{10}.\mathrm{10}.\mathrm{3}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\:.\mathrm{100}.\left(\mathrm{1}\right)^{\mathrm{2}} \:=\:\frac{\mathrm{1}}{\mathrm{2}}.\:\mathrm{10}.\mathrm{v}^{\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{v}=\:\sqrt{\mathrm{70}}\:\mathrm{m}/\mathrm{s} \\…
Question Number 40048 by rahul 19 last updated on 15/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 15/Jul/18 $${studyand}\:{solve}\:…