Question Number 39929 by rahul 19 last updated on 13/Jul/18 Answered by tanmay.chaudhury50@gmail.com last updated on 13/Jul/18 $$ \\ $$$$\mathrm{75}×\mathrm{10}=\mathrm{80}×\mathrm{10}−\mathrm{80}×{a}×{cos}\mathrm{60}^{{o}} \\ $$$$\mathrm{80}×{a}×\frac{\mathrm{1}}{\mathrm{2}}=\mathrm{50} \\ $$$${a}=\frac{\mathrm{5}}{\mathrm{4}}\:{pls}\:{check}… \\…
Question Number 39776 by ajfour last updated on 10/Jul/18 Commented by ajfour last updated on 11/Jul/18 $${Find}\:{the}\:{acceleration}\:{of}\:{wedge}, \\ $$$${if}\:{ground}\:{is}\:{smooth}\:{while}\:{the} \\ $$$${discs}\:{purely}\:{rolls}\:{on}\:{the}\:{wedge}. \\ $$$${mass}\:{of}\:{wedge}\:{is}\:{M}\:'\:={M}+{m}\:. \\ $$$${The}\:{connecting}\:{rod}\:{is}\:{light}\:{and}…
Question Number 39755 by rahul 19 last updated on 10/Jul/18 Answered by ajfour last updated on 11/Jul/18 $${a}={g}\mathrm{cot}\:\theta \\ $$$${as}\:\:\:{a}=\frac{{M}\:'{g}}{{M}+{M}\:'}\:=\:{g}\mathrm{cot}\:\theta \\ $$$$\Rightarrow\:\:\:\mathrm{1}+\frac{{M}}{{M}\:'}\:=\mathrm{tan}\:\theta \\ $$$$\Rightarrow\:\:\:\:\:{M}\:'\:=\:\frac{{M}}{\mathrm{tan}\:\theta−\mathrm{1}}\:=\:\frac{{M}\mathrm{cot}\:\theta}{\mathrm{1}−\mathrm{cot}\:\theta} \\…
Question Number 39750 by rahul 19 last updated on 10/Jul/18 Commented by rahul 19 last updated on 10/Jul/18 Commented by rahul 19 last updated on…
Question Number 39669 by rahul 19 last updated on 09/Jul/18 Answered by MrW3 last updated on 09/Jul/18 $${Before}\:{the}\:{support}\:{is}\:{removed}: \\ $$$${F}_{{k}} ={M}_{\mathrm{1}} {g}={force}\:{in}\:{spring} \\ $$$${F}_{{s}} =\left({M}_{\mathrm{1}}…
Question Number 39655 by rahul 19 last updated on 09/Jul/18 Commented by rahul 19 last updated on 09/Jul/18 $$\mathrm{Given}\:\mathrm{Mass}\:\mathrm{of}\:\mathrm{Block}\:\mathrm{A}\:=\:\mathrm{m}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{Mass}\:\mathrm{of}\:\mathrm{Block}\:\mathrm{B}\:=\:\mathrm{3m}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{acc}^{\mathrm{n}} \:\mathrm{of}\:\mathrm{blocks}\:\mathrm{at}\:\mathrm{the}\:\mathrm{instant} \\…
Question Number 39649 by rahul 19 last updated on 09/Jul/18 Commented by rahul 19 last updated on 09/Jul/18 $$\mathrm{Given}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{block}\:\mathrm{A}\:\&\:\mathrm{C}\:=\:\mathrm{m} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{mass}\:\mathrm{of}\:\mathrm{block}\:\mathrm{B}\:=\:\mathrm{2m}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{Spring}\:\mathrm{constant}\:=\:\mathrm{k}. \\ $$$$\mathrm{Find}\:\mathrm{acc}^{\mathrm{n}}…
Question Number 105076 by ajfour last updated on 25/Jul/20 Commented by ajfour last updated on 26/Jul/20 $${Let}\:{friction}\:{coefficient}\:{between} \\ $$$${ground}\:{and}\:{both}\:{semi}-{cylinders} \\ $$$${be}\:\boldsymbol{\mu}\:{given}.\:{Find}\:\alpha\:{and}\:{friction} \\ $$$${coefficient}\:{between}\:{both}\:{semi}- \\ $$$${cylindrical}\:{surfaces}\:\left(\eta\right)\:{if}\:{both}…
Question Number 105073 by Dwaipayan Shikari last updated on 25/Jul/20 $$\:{Find}\:{the}\:{centre}\:{of}\:{the}\:{mass}\:{of}\:{a}\:{cone}\:{of}\:{height}\:'{H}'\:{and}\:{Radius} \\ $$$$'{R}' \\ $$ Commented by ajfour last updated on 25/Jul/20 $${solid}\:{cone}\:{or}\:{hollow}\:? \\ $$…
Question Number 170601 by mr W last updated on 27/May/22 Commented by mr W last updated on 29/May/22 $${an}\:{uniform}\:{thin}\:{rope}\:{with}\:{length}\:{L} \\ $$$${is}\:{hanging}\:{at}\:{one}\:{end}\:{at}\:{a}\:{height}\:{of}\:{h}\: \\ $$$${above}\:{a}\:{inclined}\:{plane}\:{as}\:{shown}.\: \\ $$$${if}\:{the}\:{friction}\:{coefficient}\:{between}\:…