Question Number 169205 by novayanti_sinaga93 last updated on 26/Apr/22 $$\sqrt{\mathrm{91}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 38094 by ajfour last updated on 21/Jun/18 Commented by ajfour last updated on 21/Jun/18 $${A}\:{rod}\:{hangs}\:{from}\:{ceiling}\:{by}\:{two} \\ $$$${two}\:{strings}\:{of}\:{length}\:\boldsymbol{{a}},\:\boldsymbol{{b}}\:{from} \\ $$$${points}\:{on}\:{ceiling}\:{separated}\:{by} \\ $$$${distance}\:\boldsymbol{{d}}.\:{The}\:{rod}\:{has}\:{length}\:\boldsymbol{{l}}. \\ $$$$\boldsymbol{{F}}{ind}\:\boldsymbol{\theta}.…
Question Number 103586 by aurpeyz last updated on 15/Jul/20 Answered by OlafThorendsen last updated on 16/Jul/20 $$\overset{\rightarrow} {\mathrm{F}}_{\mathrm{1}} +\overset{\rightarrow} {\mathrm{F}}_{\mathrm{2}} +\overset{\rightarrow} {\mathrm{F}}_{\mathrm{3}} +\overset{\rightarrow} {\mathrm{P}}\:=\:\overset{\rightarrow} {\mathrm{0}}…
Question Number 103584 by aurpeyz last updated on 15/Jul/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 103585 by aurpeyz last updated on 15/Jul/20 Answered by Worm_Tail last updated on 16/Jul/20 $${CW}={ACW} \\ $$$$\:\:\:\left(\mathrm{430}×\mathrm{9}.\mathrm{8}×\mathrm{2}.\mathrm{5}\right)+\left(\mathrm{85}×\mathrm{9}.\mathrm{8}×\frac{\sqrt{\mathrm{1}.\mathrm{67}^{\mathrm{2}} +\mathrm{2}.\mathrm{5}^{\mathrm{2}} }}{\mathrm{2}}{sin}\left({tan}^{−\mathrm{1}} \frac{\mathrm{2}.\mathrm{5}}{\mathrm{1}.\mathrm{67}}\right)\right)={T}\left(\mathrm{1}.\mathrm{67}\right) \\ $$$$\:\:\:\left(\mathrm{10535}\right)+\left(\mathrm{1041}.\mathrm{25}\right)={T}\left(\mathrm{1}.\mathrm{67}\right) \\…
Question Number 103582 by aurpeyz last updated on 15/Jul/20 Commented by mr W last updated on 16/Jul/20 $${no}\:{unique}\:{solution}\:{possible}! \\ $$ Commented by mr W last…
Question Number 103450 by aurpeyz last updated on 15/Jul/20 Answered by Worm_Tail last updated on 15/Jul/20 $$\mu={tan}\theta \\ $$$$\mathrm{0}.\mathrm{35}={tan}\theta \\ $$$$\theta={tan}^{−\mathrm{1}} \mathrm{0}.\mathrm{35}=\mathrm{19}.\mathrm{29}° \\ $$ Commented…
Question Number 103448 by aurpeyz last updated on 15/Jul/20 Answered by Worm_Tail last updated on 15/Jul/20 $${u}_{{x}} =\mathrm{30}{cos}\mathrm{40}=\mathrm{22}.\mathrm{981}{m}.{s}^{−\mathrm{1}} \:{s}_{{x}} =\mathrm{28} \\ $$$$\:\:{s}_{{x}} ={u}_{{x}} {t}\Rightarrow{t}=\frac{\mathrm{28}}{\mathrm{22}.\mathrm{981}}=\mathrm{1}.\mathrm{2184} \\…
Question Number 103449 by aurpeyz last updated on 15/Jul/20 Answered by Worm_Tail last updated on 15/Jul/20 $${V}=\sqrt{{v}_{{boat}} ^{\mathrm{2}} +{v}_{{river}} ^{\mathrm{2}} −\mathrm{2}{v}_{{boat}} {v}_{{river}} {cos}\left(\mathrm{70}\right)} \\ $$$${V}=\sqrt{\mathrm{12}^{\mathrm{2}}…
Question Number 103422 by aurpeyz last updated on 15/Jul/20 Commented by Worm_Tail last updated on 15/Jul/20 $${distance}\:{moved}\:{by}\:{car}=\mathrm{60}{t} \\ $$$${distance}\:{moved}\:{by}\:{A}=\mathrm{40}{t} \\ $$$${distance}\:{moved}\:{by}\:{B}=\mathrm{40}{t} \\ $$$${total}\:{distance}\:{moved}\:{by}\:{car}\:{andB}=\mathrm{50}=\mathrm{100}{t} \\ $$$$\Rightarrow{t}=\frac{\mathrm{1}}{\mathrm{2}}…