Question Number 167078 by peter frank last updated on 05/Mar/22 Commented by mr W last updated on 07/Mar/22 $${something}\:{is}\:{tatally}\:{wrong}. \\ $$$${if}\:{the}\:{satellite}\:{is}\:{just}\:{launched}\:{into} \\ $$$${a}\:{small}\:{height},\:{say}\:{H}\approx\mathrm{0},\:{you}\:{need} \\ $$$${infinite}\:{enegy}:\:\frac{{mgR}}{\mathrm{2}}\left(\mathrm{1}+\frac{{R}}{\mathrm{0}}\right)\rightarrow\infty.…
Question Number 35771 by Tinkutara last updated on 23/May/18 Commented by Tinkutara last updated on 23/May/18 Why can't we treat D+E as a system? Commented by ajfour last updated on 23/May/18 its not clear from figure how disc D slides over the string..…
Question Number 35739 by rahul 19 last updated on 22/May/18 Commented by rahul 19 last updated on 22/May/18 Also find period of motion ? Commented by rahul 19 last updated…
Question Number 35737 by rahul 19 last updated on 22/May/18 Commented by rahul 19 last updated on 24/May/18 Thank you sir . �� Commented by ajfour last updated on…
Question Number 35567 by Tinkutara last updated on 20/May/18 Commented by Tinkutara last updated on 20/May/18 51st question please. Commented by Tinkutara last updated on 24/May/18 ?…
Question Number 101051 by aurpeyz last updated on 30/Jun/20 Commented by Dwaipayan Shikari last updated on 30/Jun/20 $${Initial}\:{K}.\:{E}=\:{P}.{E}\:+\:{work}\:\:{done}\:{by}\:{frictional}\:{force} \\ $$$$\:\:\frac{\mathrm{1}}{\mathrm{2}}{mv}^{\mathrm{2}} ={mgdsin}\mathrm{30}°+{f}.{d} \\ $$$$\:\:{d}=\frac{\mathrm{90}}{\mathrm{29}.\mathrm{5}}=\mathrm{3}.\mathrm{05}\:{metre} \\ $$…
Question Number 35474 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $${while}\:{proving}\:{F}={ma}\:{newtons}\:\mathrm{2}{nd}\:{law}\:{we}\:{put} \\ $$$${F}=\mathrm{1}\:{when}\:{m}=\mathrm{1}\:{and}\:{a}=\mathrm{1}\:{and}\:{thus}\:{k}=\mathrm{1} \\ $$$${why}\:{not}\:{F}={other}\:{value}\:{except}\:\mathrm{1}… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 35473 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $${vector}\:{has}\:{both}\:{magnetude}\:{and}\:{direction}…{then} \\ $$$${why}\:{time}\:{and}\:{current}\:{not}\:{vector}… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 100928 by ajfour last updated on 29/Jun/20 Commented by ajfour last updated on 29/Jun/20 $${Find}\:{r}\:{in}\:{terms}\:{of}\:{R}. \\ $$ Commented by ajfour last updated on…
Question Number 35258 by Tinkutara last updated on 17/May/18 Answered by ajfour last updated on 17/May/18 $${I}_{{PQ}} =\frac{{MR}^{\mathrm{2}} }{\mathrm{4}}+{M}\left(\frac{{R}}{\mathrm{4}}\right)^{\mathrm{2}} +{M}\left(\frac{\mathrm{5}{R}}{\mathrm{4}}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:=\frac{\mathrm{15}}{\mathrm{8}}{MR}^{\mathrm{2}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{15}}{\mathrm{8}}{MR}^{\mathrm{2}} \right)\left(\frac{{v}}{\mathrm{5}{R}/\mathrm{4}}\right)^{\mathrm{2}}…