Question Number 35473 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $${vector}\:{has}\:{both}\:{magnetude}\:{and}\:{direction}…{then} \\ $$$${why}\:{time}\:{and}\:{current}\:{not}\:{vector}… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 100928 by ajfour last updated on 29/Jun/20 Commented by ajfour last updated on 29/Jun/20 $${Find}\:{r}\:{in}\:{terms}\:{of}\:{R}. \\ $$ Commented by ajfour last updated on…
Question Number 35258 by Tinkutara last updated on 17/May/18 Answered by ajfour last updated on 17/May/18 $${I}_{{PQ}} =\frac{{MR}^{\mathrm{2}} }{\mathrm{4}}+{M}\left(\frac{{R}}{\mathrm{4}}\right)^{\mathrm{2}} +{M}\left(\frac{\mathrm{5}{R}}{\mathrm{4}}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:=\frac{\mathrm{15}}{\mathrm{8}}{MR}^{\mathrm{2}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{15}}{\mathrm{8}}{MR}^{\mathrm{2}} \right)\left(\frac{{v}}{\mathrm{5}{R}/\mathrm{4}}\right)^{\mathrm{2}}…
Question Number 35174 by ajfour last updated on 16/May/18 Commented by ajfour last updated on 16/May/18 $${Q}.\mathrm{35136}\:\:\:\left({solution}\right) \\ $$ Answered by ajfour last updated on…
Question Number 35136 by Tinkutara last updated on 15/May/18 Commented by ajfour last updated on 16/May/18 $${See}\:\:{Q}.\mathrm{35174} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 100629 by aurpeyz last updated on 27/Jun/20 Commented by aurpeyz last updated on 27/Jun/20 $$\mathrm{question}\:\mathrm{3}\:\mathrm{pls} \\ $$ Answered by mr W last updated…
Question Number 100498 by ugwu Kingsley last updated on 27/Jun/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 34781 by Tinkutara last updated on 11/May/18 Answered by ajfour last updated on 11/May/18 $$\mathrm{6}{mgx}_{\mathrm{1}} −\mathrm{3}{mgx}_{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{18}{m}\right){v}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}{kx}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…..\left({i}\right) \\ $$$${x}_{\mathrm{1}} −{x}_{\mathrm{2}}…
Question Number 34765 by Tinkutara last updated on 10/May/18 Answered by ajfour last updated on 11/May/18 $${should}\:{be}\:{tensile}\:\:{so}\:\:\left(\mathrm{3}\right). \\ $$ Commented by Tinkutara last updated on…
Question Number 34703 by NECx last updated on 10/May/18 $${A}\:{man}\:{pushes}\:{a}\:{box}\:{of}\:\mathrm{40}{kg}\:{up}\:{an} \\ $$$${incline}\:{of}\:\mathrm{15}°,{if}\:{the}\:{man}\:{applies} \\ $$$${a}\:{horizontal}\:{force}\:\mathrm{200}{N}\:{and}\:{the} \\ $$$${box}\:{moves}\:{up}\:{the}\:{plane}\:{a}\:{distance} \\ $$$${of}\:\mathrm{20}{m}\:{at}\:{a}\:{constant}\:{velocity}\:{and} \\ $$$${the}\:{coefficient}\:{of}\:{friction}\:{is}\:\mathrm{0}.\mathrm{1}, \\ $$$${find}\: \\ $$$$\left.{a}\right){the}\:{workdone}\:{by}\:{the}\:{man}\:{on}\:{the} \\…