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Category: Mechanics

Question-165296

Question Number 165296 by ajfour last updated on 28/Jan/22 Commented by ajfour last updated on 28/Jan/22 $${If}\:{when}\:{the}\:{disc}\:{rolls}\:{down}\:{and}\:{is} \\ $$$$\:{about}\:{to}\:{to}\:{hit}\:{the}\:{pivot},\:{the}\:{rod} \\ $$$${gets}\:{horizontal},\:{find}\:{initial}\:{angle} \\ $$$$\theta\:{at}\:{which}\:{system}\:{is}\:{released}. \\ $$$$\left({assume}\:{pure}\:{rolling}\:{throughout}\right)…

A-car-with-a-mass-of-1300kg-is-constructed-so-that-its-frame-is-suspended-by-four-strings-Each-has-a-force-constant-of-20000N-m-Two-people-riding-the-car-have-a-combined-mass-of-160kg-Find-the-frequ

Question Number 33542 by NECx last updated on 18/Apr/18 $${A}\:{car}\:{with}\:{a}\:{mass}\:{of}\:\mathrm{1300}{kg}\:{is} \\ $$$${constructed}\:{so}\:{that}\:{its}\:{frame}\:{is}\: \\ $$$${suspended}\:{by}\:{four}\:{strings}.{Each} \\ $$$${has}\:{a}\:{force}\:{constant}\:{of}\:\mathrm{20000}{N}/{m}. \\ $$$${Two}\:{people}\:{riding}\:{the}\:{car}\:{have}\:{a} \\ $$$${combined}\:{mass}\:{of}\:\mathrm{160}{kg}.{Find}\:{the} \\ $$$${frequency}\:{of}\:{vibration}\:{of}\:{the}\:{car}. \\ $$ Commented…

A-mass-of-2kg-is-attached-to-a-spring-with-constant-8N-m-It-is-then-displaced-to-the-point-x-2-What-time-does-it-take-for-the-block-to-travel-to-the-point-x-1-a-40s-b-60s-c-30s-d-20s-

Question Number 33533 by NECx last updated on 18/Apr/18 $${A}\:{mass}\:{of}\:\mathrm{2}{kg}\:{is}\:{attached}\:{to}\:{a} \\ $$$${spring}\:{with}\:{constant}\:\mathrm{8}{N}/{m}.{It}\:{is}\circledast \\ $$$${then}\:{displaced}\:{to}\:{the}\:{point}\:{x}=\mathrm{2}. \\ $$$${What}\:{time}\:{does}\:{it}\:{take}\:{for}\:{the}\:{block} \\ $$$${to}\:{travel}\:{to}\:{the}\:{point}\:{x}=\mathrm{1}? \\ $$$$\left.{a}\left.\right)\left.\mathrm{4}\left.\mathrm{0}{s}\:{b}\right)\mathrm{60}{s}\:{c}\right)\mathrm{30}{s}\:{d}\right)\mathrm{20}{s} \\ $$ Answered by ajfour…

If-the-frequency-of-0-75-long-simple-pendulum-is-1-5Hz-the-angular-frequency-on-a-corresponding-reference-circle-in-rad-s-is-a-1-5pi-b-3pi-c-0-5pi-d-2pi-

Question Number 33535 by NECx last updated on 18/Apr/18 $${If}\:{the}\:{frequency}\:{of}\:\mathrm{0}.\mathrm{75}\:{long}\:{simple} \\ $$$${pendulum}\:{is}\:\mathrm{1}.\mathrm{5}{Hz},{the}\:{angular} \\ $$$${frequency}\:{on}\:{a}\:{corresponding} \\ $$$${reference}\:{circle}\:{in}\:{rad}/{s}\:{is} \\ $$$$\left.{a}\left.\right)\left.\mathrm{1}\left..\mathrm{5}\pi\:{b}\right)\mathrm{3}\pi\:{c}\right)\mathrm{0}.\mathrm{5}\pi\:{d}\right)\mathrm{2}\pi \\ $$ Answered by ajfour last updated…

Question-164345

Question Number 164345 by mr W last updated on 16/Jan/22 Commented by mr W last updated on 18/Jan/22 $${rod}\:{with}\:{mass}\:{m}\:{and}\:{length}\:{b}\:{rests} \\ $$$${in}\:{a}\:{frictionless}\:{parabolic}\:{cup}\:{as} \\ $$$${shown}.\:{find}\:{the}\:{time}\:{period}\:{of} \\ $$$${oscillations}\:{of}\:{the}\:{rod}.…

The-resistance-R-of-an-unknown-resistor-is-found-by-measuring-the-potential-difference-V-across-the-resistor-and-the-current-I-through-it-and-using-the-equation-R-V-I-The-voltmeter-reading-has-a-3

Question Number 33272 by NECx last updated on 14/Apr/18 $${The}\:\boldsymbol{{resistance}}\:\boldsymbol{{R}}\:\boldsymbol{{of}}\:\boldsymbol{{an}}\: \\ $$$$\boldsymbol{{unknown}}\:\boldsymbol{{resistor}}\:\boldsymbol{{is}}\:\boldsymbol{{found}}\:\boldsymbol{{by}} \\ $$$$\boldsymbol{{measuring}}\:\boldsymbol{{the}}\:\boldsymbol{{potential}} \\ $$$$\boldsymbol{{difference}}\:\boldsymbol{{V}}\:\boldsymbol{{across}}\:\boldsymbol{{the}} \\ $$$$\boldsymbol{{resistor}}\:\boldsymbol{{and}}\:\boldsymbol{{the}}\:\boldsymbol{{current}}\:\boldsymbol{{I}}\:\boldsymbol{{through}} \\ $$$$\boldsymbol{{it}}\:\boldsymbol{{and}}\:\boldsymbol{{using}}\:\boldsymbol{{the}}\:\boldsymbol{{equation}}\:\boldsymbol{{R}}=\frac{{V}}{{I}}. \\ $$$$\boldsymbol{{The}}\:\boldsymbol{{voltmeter}}\:\boldsymbol{{reading}}\:\boldsymbol{{has}}\:\boldsymbol{{a}}\:\mathrm{3\%} \\ $$$$\boldsymbol{{uncertainty}}\:\boldsymbol{{and}}\:\boldsymbol{{the}}\:\boldsymbol{{ammeter}} \\…

Question-33239

Question Number 33239 by Tinkutara last updated on 13/Apr/18 Answered by ajfour last updated on 14/Apr/18 $$\mathrm{2}\left[{mu}\mathrm{cos}\:\left(\frac{\alpha}{\mathrm{2}}\right)\right]=\left(\mathrm{2}{m}\right)\left(\frac{{u}}{\mathrm{2}}\right) \\ $$$$\Rightarrow\:\:\mathrm{cos}\:\left(\frac{\alpha}{\mathrm{2}}\right)=\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\:\Rightarrow\:\:\alpha\:=\:\mathrm{120}°\:. \\ $$ Commented by Tinkutara last…

Question-33214

Question Number 33214 by Tinkutara last updated on 13/Apr/18 Commented by Tinkutara last updated on 13/Apr/18 Commented by Tinkutara last updated on 15/Apr/18 But if we consider the torque of mg instead of ma it still gives approximately the same answer. Which one is conceptually correct? Commented…