Question Number 32440 by Tinkutara last updated on 25/Mar/18 Answered by ajfour last updated on 25/Mar/18 $$\mathrm{5}{g}−{T}=\mathrm{5}\left(\mathrm{2}{a}\right) \\ $$$$\mathrm{2}{T}−\mathrm{5}{g}=\mathrm{5}{a} \\ $$$$\Rightarrow\:\:\mathrm{5}{g}−{T}=\mathrm{4}{T}−\mathrm{10}{g} \\ $$$$\Rightarrow\:\:\:{T}=\mathrm{30}{N}\:. \\ $$…
Question Number 32236 by momo last updated on 22/Mar/18 Answered by ajfour last updated on 22/Mar/18 $${a}=\frac{{Mg}\mathrm{sin}\:\theta_{{S}} }{\frac{\mathrm{7}}{\mathrm{5}}{MR}^{\mathrm{2}} }\:=\:\frac{{mg}\mathrm{sin}\:\theta_{{C}} }{\frac{\mathrm{3}}{\mathrm{2}}{mR}^{\mathrm{2}} } \\ $$$$\Rightarrow\:\:\:\frac{\mathrm{sin}\:\theta_{{C}} }{\mathrm{sin}\:\theta_{{S}} }\:\:=\:\:\frac{\mathrm{15}}{\mathrm{14}}\:\:.…
Question Number 32233 by momo last updated on 22/Mar/18 $${A}\:{particle}\:{id}\:{moving}\:{in}\:{a}\:{circular} \\ $$$${path}\:{of}\:{radius}\:{a}\:{with}\:{constant} \\ $$$${velocity}\:{v}.{The}\:{center}\:{of}\:{cirvle} \\ $$$${marked}\:{by}\:{C}.{The}\:{angular}\:{momentum} \\ $$$${from}\:{the}\:{origin}\:{is}. \\ $$ Commented by momo last updated…
Question Number 163293 by ajfour last updated on 05/Jan/22 Commented by ajfour last updated on 05/Jan/22 $${If}\:{the}\:{plank}\:{rests}\:{on}\:{two}\:{fixed}\:{cylinders} \\ $$$${in}\:{contact}\:{with}\:{each}\:{other}\:{and}\: \\ $$$${ground},\:{and}\:{if}\:{the}\:{bottom}\:{edge}\:{of} \\ $$$${plank}\:{is}\:{just}\:{bit}\:{above}\:{ground},{find} \\ $$$${friction}\:{coefficient}\:\mu_{{min}}…
Question Number 32218 by Tinkutara last updated on 21/Mar/18 Answered by mrW2 last updated on 21/Mar/18 Commented by mrW2 last updated on 22/Mar/18 $${N}_{\mathrm{1}} ×\frac{{h}}{\mathrm{sin}\:\theta}={mg}×\frac{{l}\:\mathrm{cos}\:\theta}{\mathrm{2}\:}…
Question Number 32191 by ajfour last updated on 21/Mar/18 Commented by ajfour last updated on 21/Mar/18 $${Find}\:{maximum}\:{distance}\:{from} \\ $$$${foot}\:{of}\:{building}\:{where}\:{projectile} \\ $$$${can}\:{land}.\:\left({Ignore}\:{air}\:{resistance}\right). \\ $$ Answered by…
Question Number 32098 by Tinkutara last updated on 19/Mar/18 Commented by ajfour last updated on 19/Mar/18 $$\frac{\mathrm{3}{L}}{\mathrm{4}}\:\:. \\ $$ Commented by Tinkutara last updated on…
Question Number 97628 by peter frank last updated on 08/Jun/20 Answered by Rio Michael last updated on 08/Jun/20 $$\mathrm{Assume}\:\mathrm{the}\:\mathrm{thickness}\:\mathrm{of}\:\mathrm{each}\:\mathrm{piece}\:=\:{h}\:\:\mathrm{and}\:\mathrm{the} \\ $$$$\mathrm{acceleration}\:\mathrm{produced}\:\mathrm{by}\:\mathrm{each}\:\mathrm{piece}\:=\:{a} \\ $$$$\mathrm{from}\:{v}_{{f}} ^{\mathrm{2}} \:−{v}_{\mathrm{0}}…
Question Number 97629 by peter frank last updated on 08/Jun/20 Answered by Rio Michael last updated on 09/Jun/20 $$\:\mathrm{mass}\:\mathrm{of}\:\mathrm{man}\:=\:\mathrm{100}\:\mathrm{kg} \\ $$$$\mathrm{height}\:\mathrm{jumped}\:=\:\mathrm{5}\:\mathrm{m} \\ $$$$\mathrm{time}\:=\:\mathrm{0}.\mathrm{4}\:\mathrm{s} \\ $$$$\:\mathrm{Velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{dude}\:{v}\:=\:\sqrt{\mathrm{2}{gh}}\:=\:\sqrt{\mathrm{2}\:×\:\mathrm{9}.\mathrm{8}\:\mathrm{ms}^{−\mathrm{2}}…
Question Number 32074 by NECx last updated on 19/Mar/18 $${A}\:{machine}\:{with}\:{a}\:{velocity}\:{ratio} \\ $$$${of}\:\mathrm{5}\:{requires}\:\mathrm{150}{J}\:{of}\:{work}\:{to}\:{raise} \\ $$$${a}\:\mathrm{500}{N}\:{load}\:{through}\:{a}\:{vertical} \\ $$$${distance}\:{of}\:\mathrm{200}{cm}.{Calculate} \\ $$$$\left.{a}\right){the}\:{efficiency}\:{of}\:{the}\:{machine} \\ $$$$\left.{b}\right){the}\:{mechanical}\:{advantage}\:{of} \\ $$$${the}\:{machine}. \\ $$ Commented…