Category: Mechanics

Question Number 35737 by rahul 19 last updated on 22/May/18 Commented by rahul 19 last updated on 24/May/18 Thank you sir . �� Commented by ajfour last updated on…

Question Number 101051 by aurpeyz last updated on 30/Jun/20 Commented by Dwaipayan Shikari last updated on 30/Jun/20 $$InitialK.E=P.E+workdonebyfrictionalforce$$$$\frac{1}{2}{mv}^2=mgdsin30°+f.d$$$$d=\frac{90}{29.5}=3.05metre$$…

Question Number 35473 by tanmay.chaudhury50@gmail.com last updated on 19/May/18 $$vectorhasbothmagnetudeanddirection\dots then$$$$whytimeandcurrentnotvector\dots$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 35258 by Tinkutara last updated on 17/May/18 Answered by ajfour last updated on 17/May/18 $$I_{PQ}=\frac{{MR}^2}{4}+M{\left(\frac{R}{4}\right)}^2+M{\left(\frac{5R}{4}\right)}^2$$$$=\frac{15}{8}{MR}^2$$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{15}}{\mathrm{8}}{MR}^{\mathrm{2}} \right)\left(\frac{{v}}{\mathrm{5}{R}/\mathrm{4}}\right)^{\mathrm{2}}…

Question Number 35136 by Tinkutara last updated on 15/May/18 Commented by ajfour last updated on 16/May/18 $$SeeQ.35174$$ Terms of Service Privacy Policy Contact:…