Question Number 97628 by peter frank last updated on 08/Jun/20 Answered by Rio Michael last updated on 08/Jun/20 $$\mathrm{Assume}\:\mathrm{the}\:\mathrm{thickness}\:\mathrm{of}\:\mathrm{each}\:\mathrm{piece}\:=\:{h}\:\:\mathrm{and}\:\mathrm{the} \\ $$$$\mathrm{acceleration}\:\mathrm{produced}\:\mathrm{by}\:\mathrm{each}\:\mathrm{piece}\:=\:{a} \\ $$$$\mathrm{from}\:{v}_{{f}} ^{\mathrm{2}} \:−{v}_{\mathrm{0}}…
Question Number 97629 by peter frank last updated on 08/Jun/20 Answered by Rio Michael last updated on 09/Jun/20 $$\:\mathrm{mass}\:\mathrm{of}\:\mathrm{man}\:=\:\mathrm{100}\:\mathrm{kg} \\ $$$$\mathrm{height}\:\mathrm{jumped}\:=\:\mathrm{5}\:\mathrm{m} \\ $$$$\mathrm{time}\:=\:\mathrm{0}.\mathrm{4}\:\mathrm{s} \\ $$$$\:\mathrm{Velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{dude}\:{v}\:=\:\sqrt{\mathrm{2}{gh}}\:=\:\sqrt{\mathrm{2}\:×\:\mathrm{9}.\mathrm{8}\:\mathrm{ms}^{−\mathrm{2}}…
Question Number 32074 by NECx last updated on 19/Mar/18 $${A}\:{machine}\:{with}\:{a}\:{velocity}\:{ratio} \\ $$$${of}\:\mathrm{5}\:{requires}\:\mathrm{150}{J}\:{of}\:{work}\:{to}\:{raise} \\ $$$${a}\:\mathrm{500}{N}\:{load}\:{through}\:{a}\:{vertical} \\ $$$${distance}\:{of}\:\mathrm{200}{cm}.{Calculate} \\ $$$$\left.{a}\right){the}\:{efficiency}\:{of}\:{the}\:{machine} \\ $$$$\left.{b}\right){the}\:{mechanical}\:{advantage}\:{of} \\ $$$${the}\:{machine}. \\ $$ Commented…
Question Number 32075 by NECx last updated on 19/Mar/18 $${A}\:{rigid}\:{uniform}\:{bar}\:{of}\:{length}\:\mathrm{2}.\mathrm{4}{m} \\ $$$${is}\:{pivoted}\:{horizontally}\:{at}\:{its}\:{mid}-{point}. \\ $$$${Weights}\:{are}\:{hung}\:{from}\:{two}\:{points} \\ $$$${of}\:{the}\:{bar}\:{such}\:{that}\:{a}\:\mathrm{200}{N}\:{is}\:{at} \\ $$$${the}\:\mathrm{0}.\mathrm{4}{m}\:{mark}\:{and}\:{a}\:\mathrm{300}{N}\:{is}\:{at} \\ $$$$\mathrm{1}.\mathrm{6}{m}\:{mark}.{To}\:{maintain} \\ $$$${horizontal}\:{equilibrum}\:{a}\:{couple}\:{is} \\ $$$${applied}\:{to}\:{the}\:{bar}.\:{What}\:{is}\:{the} \\…
Question Number 163053 by ajfour last updated on 03/Jan/22 Commented by ajfour last updated on 03/Jan/22 $${Q}.\mathrm{162949}\:\:\left({revisit}\right) \\ $$ Answered by ajfour last updated on…
Question Number 31957 by Tinkutara last updated on 17/Mar/18 Commented by Tinkutara last updated on 17/Mar/18 In this question two answers are possible. Are both correct? Answered by ajfour last updated on 19/Mar/18 $${If}\:\mathrm{10}{N}\:{force}\:{is}\:{load},…
Question Number 31934 by NECx last updated on 17/Mar/18 $${The}\:{flywheel}\:{of}\:{a}\:{punch}\:{press}\:{has} \\ $$$${a}\:{moment}\:{of}\:{inertia}\:{of}\:\mathrm{16}{kgm}^{\mathrm{2}} \\ $$$${and}\:{runs}\:{at}\:\mathrm{300}{rev}/{min}.{The} \\ $$$${flywheel}\:{supplies}\:{all}\:{the}\:{energy} \\ $$$${needed}\:{in}\:{a}\:{quick}\:{punching} \\ $$$${operation}. \\ $$$$\left.{a}\right){Find}\:{the}\:{speed}\:{in}\:{rev}/{min}\:{to} \\ $$$${which}\:{the}\:{flywheel}\:{will}\:{be}\:{reduced} \\…
Question Number 31935 by NECx last updated on 17/Mar/18 $${The}\:{rigid}\:{body}\:{of}\:{mass}\:\mathrm{10}{kg} \\ $$$${rotates}\:{such}\:{that}\:{the}\:{radius}\:{of}\:{the} \\ $$$${circular}\:{path}\:{it}\:{describes}\:{is}\:\mathrm{5}{cm}.{It} \\ $$$${it}\:{moves}\:{from}\:{the}\:{point}\:{P}\:{to}\:{Q}\:{in} \\ $$$$\mathrm{5}{s}\:{covering}\:{an}\:{angular}\:{distance} \\ $$$${of}\:\mathrm{30}°,{Calculate}\:: \\ $$$$\left.{a}\right){the}\:{final}\:{angular}\:{velocity}\:{if} \\ $$$${the}\:{angular}\:{acceleration}\:{is}\:\mathrm{4}{m}/{s}^{\mathrm{2}} \\…
Question Number 31933 by NECx last updated on 17/Mar/18 $${The}\:{sides}\:{of}\:{a}\:{cubical}\:{container} \\ $$$${are}\:{given}\:{by}\:{the}\:{vectors} \\ $$$${a}_{\mathrm{1}} =\mathrm{2}{i}+\mathrm{3}{j}−\mathrm{4}{k},{a}_{\mathrm{2}} ={i}+\mathrm{2}{j}−\mathrm{3}{k}, \\ $$$${a}_{\mathrm{3}} =\mathrm{3}{i}+\mathrm{6}{j}−\mathrm{4}{k}.{What}\:{is}\:{the}\:{volumr} \\ $$$${of}\:{the}\:{container}? \\ $$ Answered by…
Question Number 31894 by Tinkutara last updated on 16/Mar/18 Commented by Tinkutara last updated on 16/Mar/18 Can you explain with diagrams please? I can't understand in which direction forces are balanced. Commented by mrW2 last updated on 16/Mar/18 $${m}\left({v}\:\mathrm{cos}\:\theta\right)^{\mathrm{2}}…