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Category: Mechanics

Question-162949

Question Number 162949 by ajfour last updated on 02/Jan/22 Commented by ajfour last updated on 02/Jan/22 $${If}\:{the}\:{semi}\:{ring}\:{plus}\:{rod}\:{combina}^{{n}} , \\ $$$${having}\:{the}\:{same}\:{linear}\:{mass}\:{dens}- \\ $$$${ity}\:{is}\:{released}\:{as}\:{shown},\:{how}\:{long}\: \\ $$$${does}\:{it}\:{take}\:{to}\:{turn}\:{around}\:{the}\:{pivot} \\…

Question-31835

Question Number 31835 by Tinkutara last updated on 15/Mar/18 Commented by mrW2 last updated on 15/Mar/18 $${direction}\:{of}\:{angular}\:{velocity}\:{is} \\ $$$${toward}\:{driver}'{s}\:{left} \\ $$$$ \\ $$$${direction}\:{of}\:{angular}\:{acceleration}\:{is} \\ $$$${toward}\:{driver}'{s}\:{right}…

Calculate-the-moment-of-inertia-of-the-earth-abouth-its-axis-If-the-mass-of-the-earth-is-6-0-10-34-kg-and-radius-6-4-10-6-m-Assume-the-earth-to-be-a-perfect-sphere-

Question Number 31766 by NECx last updated on 14/Mar/18 $${Calculate}\:{the}\:{moment}\:{of}\:{inertia} \\ $$$${of}\:{the}\:{earth}\:{abouth}\:{its}\:{axis}.{If} \\ $$$${the}\:{mass}\:{of}\:{the}\:{earth}\:{is}\:\mathrm{6}.\mathrm{0}×\mathrm{10}^{\mathrm{34}} {kg} \\ $$$${and}\:{radius}\:\mathrm{6}.\mathrm{4}×\mathrm{10}^{\mathrm{6}} {m}. \\ $$$$\left({Assume}\:{the}\:{earth}\:{to}\:{be}\:{a}\:{perfect}\right. \\ $$$$\left.{sphere}\right) \\ $$ Commented…

Systems-of-particles-doubt-

Question Number 31628 by Tinkutara last updated on 11/Mar/18 $${Systems}\:{of}\:{particles}\:{doubt} \\ $$ Commented by Tinkutara last updated on 11/Mar/18 If a rigid object has only rotational motion about a fixed axis are there any points within the object that always have the same velocity as the centre of mass? If so which ones? Commented by mrW2 last updated…

Question-31566

Question Number 31566 by ajfour last updated on 10/Mar/18 Commented by ajfour last updated on 10/Mar/18 $${Frame}\:{XYZ}\:{is}\:{fixed}.\:{Frame}\:{xyz} \\ $$$${rotates}\:{with}\:{angular}\:{velocity}\:\Omega. \\ $$$${Relate}\:{acceleration}\:{of}\:{particle}\: \\ $$$${in}\:{fixed}\:{frame}\:{to}\:{that}\:{in}\:{rotating} \\ $$$${frame}.…

From-a-circular-disc-of-radius-R-a-circular-hole-of-radius-R-2-is-cut-out-The-centre-of-the-circular-hole-is-at-R-2-from-the-centre-of-the-original-disc-Locate-the-centre-of-gravity-of-the-resulting-f

Question Number 31476 by NECx last updated on 09/Mar/18 $${From}\:{a}\:{circular}\:{disc}\:{of}\:{radius}\:{R} \\ $$$${a}\:{circular}\:{hole}\:{of}\:{radius}\:{R}/\mathrm{2}\:{is} \\ $$$${cut}\:{out}.{The}\:{centre}\:{of}\:{the}\:{circular} \\ $$$${hole}\:{is}\:{at}\:{R}/\mathrm{2}\:{from}\:{the}\:{centre}\:{of} \\ $$$${the}\:{original}\:{disc}.{Locate}\:{the}\:{centre} \\ $$$${of}\:{gravity}\:{of}\:{the}\:{resulting}\:{flat} \\ $$$${body}. \\ $$$$ \\…