Question Number 31144 by NECx last updated on 03/Mar/18 $${A}\:{mass}\:{oscillating}\:{on}\:{a}\:{spring} \\ $$$${has}\:{amplitude}\:{of}\:\mathrm{1}.\mathrm{2}{m}\:{and}\:{a} \\ $$$${period}\:{of}\:\mathrm{2}.\mathrm{0}{s}. \\ $$$$\left({a}\right){Deduce}\:{the}\:{equation}\:{for}\:{the} \\ $$$${displacement}\:{x}\:{if}\:{the}\:{timing}\:{starts} \\ $$$${at}\:{the}\:{instant}\:{where}\:{the}\:{mass} \\ $$$${has}\:{its}\:{maximum}\:{displacement}. \\ $$$$\left.{b}\right){calculate}\:{the}\:{time}\:{interval} \\…
Question Number 31133 by Tinkutara last updated on 02/Mar/18 Commented by ajfour last updated on 03/Mar/18 Commented by ajfour last updated on 03/Mar/18 $$\omega_{{max}} =\frac{\sqrt{{u}^{\mathrm{2}}…
Question Number 31026 by Tinkutara last updated on 02/Mar/18 Commented by Tinkutara last updated on 02/Mar/18 Commented by Tinkutara last updated on 02/Mar/18 39 question Terms…
Question Number 30994 by ajfour last updated on 01/Mar/18 Commented by ajfour last updated on 01/Mar/18 Commented by ajfour last updated on 01/Mar/18 $${Please}\:{solve}.\:{Free}\:{body}\:{diagrams} \\…
Question Number 30984 by rahul 19 last updated on 01/Mar/18 Commented by ajfour last updated on 03/Mar/18 $${Balancing}\:{torque}\:{about}\:{B}\: \\ $$$${Rl}−{mg}\left(\frac{\mathrm{2}{l}}{\mathrm{3}}\right)=\mathrm{0} \\ $$$$\Rightarrow\:\:\:\boldsymbol{{R}}=\frac{\mathrm{2}\boldsymbol{{mg}}}{\mathrm{3}}\:\:\:\:\:\:\Rightarrow\:\:\:\boldsymbol{{n}}=\mathrm{2}\:\:\:. \\ $$ Commented…
Question Number 30961 by Tinkutara last updated on 01/Mar/18 Commented by ajfour last updated on 01/Mar/18 $$\left(\mathrm{4}\right)\:\:\:{if}\:{it}\:{did}\:{not}\:{start}\:{from}\:{rest}. \\ $$ Commented by MJS last updated on…
Question Number 30875 by Tinkutara last updated on 27/Feb/18 Commented by ajfour last updated on 28/Feb/18 $${sorry},\:{its}\:{just}\:\left(\mathrm{3}\right)\:{that}\:{is}\:{incorrect}. \\ $$ Answered by ajfour last updated on…
Question Number 30738 by NECx last updated on 25/Feb/18 $${A}\:{boy}\:{can}\:{swim}\:{with}\:{a}\:{speed}\:{of} \\ $$$$\mathrm{26}{m}/{s}\:{in}\:{still}\:{water}.{He}\:{wants}\:{to} \\ $$$${swim}\:{across}\:{a}\:\mathrm{150}{m}\:{river}\:{from} \\ $$$${a}\:{point}\:{A}\:{to}\:{point}\:{B}\:{which}\:{is}\: \\ $$$${directly}\:{opposite}\:{the}\:{other}\:{side} \\ $$$${of}\:{the}\:{river}.{The}\:{river}\:{flows}\:{with} \\ $$$${a}\:{speed}\:{of}\:\mathrm{10}{m}/{s}. \\ $$$$\left.{i}\right){if}\:{he}\:{always}\:{swim}\:{in}\:{the}\: \\…
Question Number 161783 by ajfour last updated on 22/Dec/21 Commented by ajfour last updated on 22/Dec/21 $${Cylinder}\:{is}\:{free}\:{to}\:{purely}\:{roll},\:{find} \\ $$$${radius},\:{if}\:{point}\:{mass}\:{ball}\:{is}\:{to}\:{be} \\ $$$${received}\:{successfully}. \\ $$ Commented by…
Question Number 30628 by Tinkutara last updated on 23/Feb/18 Answered by ajfour last updated on 23/Feb/18 $${MV}_{{recoil}} ={m}\left({u}−{V}_{{recoil}} \right) \\ $$$$\Rightarrow\:{V}_{{recoil}} =\:\frac{{mu}}{{M}+{m}}\:. \\ $$ Commented…