Question Number 30994 by ajfour last updated on 01/Mar/18 Commented by ajfour last updated on 01/Mar/18 Commented by ajfour last updated on 01/Mar/18 $${Please}\:{solve}.\:{Free}\:{body}\:{diagrams} \\…
Question Number 30984 by rahul 19 last updated on 01/Mar/18 Commented by ajfour last updated on 03/Mar/18 $${Balancing}\:{torque}\:{about}\:{B}\: \\ $$$${Rl}−{mg}\left(\frac{\mathrm{2}{l}}{\mathrm{3}}\right)=\mathrm{0} \\ $$$$\Rightarrow\:\:\:\boldsymbol{{R}}=\frac{\mathrm{2}\boldsymbol{{mg}}}{\mathrm{3}}\:\:\:\:\:\:\Rightarrow\:\:\:\boldsymbol{{n}}=\mathrm{2}\:\:\:. \\ $$ Commented…
Question Number 30961 by Tinkutara last updated on 01/Mar/18 Commented by ajfour last updated on 01/Mar/18 $$\left(\mathrm{4}\right)\:\:\:{if}\:{it}\:{did}\:{not}\:{start}\:{from}\:{rest}. \\ $$ Commented by MJS last updated on…
Question Number 30875 by Tinkutara last updated on 27/Feb/18 Commented by ajfour last updated on 28/Feb/18 $${sorry},\:{its}\:{just}\:\left(\mathrm{3}\right)\:{that}\:{is}\:{incorrect}. \\ $$ Answered by ajfour last updated on…
Question Number 30738 by NECx last updated on 25/Feb/18 $${A}\:{boy}\:{can}\:{swim}\:{with}\:{a}\:{speed}\:{of} \\ $$$$\mathrm{26}{m}/{s}\:{in}\:{still}\:{water}.{He}\:{wants}\:{to} \\ $$$${swim}\:{across}\:{a}\:\mathrm{150}{m}\:{river}\:{from} \\ $$$${a}\:{point}\:{A}\:{to}\:{point}\:{B}\:{which}\:{is}\: \\ $$$${directly}\:{opposite}\:{the}\:{other}\:{side} \\ $$$${of}\:{the}\:{river}.{The}\:{river}\:{flows}\:{with} \\ $$$${a}\:{speed}\:{of}\:\mathrm{10}{m}/{s}. \\ $$$$\left.{i}\right){if}\:{he}\:{always}\:{swim}\:{in}\:{the}\: \\…
Question Number 161783 by ajfour last updated on 22/Dec/21 Commented by ajfour last updated on 22/Dec/21 $${Cylinder}\:{is}\:{free}\:{to}\:{purely}\:{roll},\:{find} \\ $$$${radius},\:{if}\:{point}\:{mass}\:{ball}\:{is}\:{to}\:{be} \\ $$$${received}\:{successfully}. \\ $$ Commented by…
Question Number 30628 by Tinkutara last updated on 23/Feb/18 Answered by ajfour last updated on 23/Feb/18 $${MV}_{{recoil}} ={m}\left({u}−{V}_{{recoil}} \right) \\ $$$$\Rightarrow\:{V}_{{recoil}} =\:\frac{{mu}}{{M}+{m}}\:. \\ $$ Commented…
Question Number 30614 by NECx last updated on 23/Feb/18 $${Consider}\:{that}\:{two}\:{cars}\:{are}\: \\ $$$${accelerating}\:{along}\:{the}\:{same}\:{road} \\ $$$${and}\:{if}\:{the}\:{distance}\:{between}\:{them} \\ $$$${was}\:{observed}\:{to}\:{be}\:{increasing},{what} \\ $$$${deduction}\:{can}\:{you}\:{make}\:{as}\:{regards} \\ $$$${the}\:{acceleration}? \\ $$$$\left.{a}\right){it}\:{implies}\:{that}\:{the}\:{trailing}\:{car} \\ $$$${has}\:{the}\:{smaller}\:{acceleration} \\…
Question Number 30615 by Tinkutara last updated on 23/Feb/18 Answered by ajfour last updated on 23/Feb/18 $$\bar {{r}}={t}^{\mathrm{2}} \hat {{i}}+\mathrm{3}{t}^{\mathrm{2}} \hat {{j}} \\ $$$$\bar {{v}}=\:\mathrm{2}{t}\hat…
Question Number 30613 by NECx last updated on 23/Feb/18 $${A}\:{car}\:{negotiates}\:{a}\:{bend}\:{of}\:{radius} \\ $$$$\mathrm{20}{m}\:{with}\:{an}\:{acceleration}\:{of}\: \\ $$$$\mathrm{12}{m}/{s}^{\mathrm{2}} .{What}\:{is}\:{the}\:{maximum} \\ $$$${speed}\:{the}\:{car}\:{can}\:{attain}\:{without} \\ $$$${skidding}? \\ $$ Commented by NECx last…