Question Number 28179 by Tinkutara last updated on 21/Jan/18 Commented by Tinkutara last updated on 21/Jan/18 I have done A and B. Please help in C. Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28171 by ajfour last updated on 21/Jan/18 Commented by ajfour last updated on 21/Jan/18 $${Q}.\mathrm{28113}\:\:{another}\:{solution}: \\ $$ Answered by ajfour last updated on…
Question Number 28113 by ajfour last updated on 20/Jan/18 Commented by ajfour last updated on 20/Jan/18 $${If}\:{system}\:{of}\:{disc},\:{spring},\:{and} \\ $$$${block}\:{of}\:{mass}\:\boldsymbol{{m}},\:{be}\:{released}\:{from} \\ $$$${rest}\:{with}\:{spring}\:{in}\:{natural}\:{length}, \\ $$$$\left({friction}\:{being}\:{sufficent}\:{to}\right. \\ $$$$\left.{prevent}\:{slipping}\right)\:{find}\:{maximum}…
Question Number 28050 by ajfour last updated on 19/Jan/18 Commented by ajfour last updated on 19/Jan/18 $${The}\:{blue}\:{disc},\:{radius}\:\boldsymbol{{r}},{mass}\:\boldsymbol{{m}}, \\ $$$${rolls}\:{on}\:{the}\:{ground}\:{in}\:{a}\:{circle}\:{of} \\ $$$${radius}\:\boldsymbol{{R}}.\:{It}\:{rolls}\:{and}\:{its}\:{axis} \\ $$$${maintains}\:{a}\:{constant}\:{angle}\:{with} \\ $$$${the}\:{horizontal}\:{plane}.\:{Assuming}…
Question Number 93568 by kikomssn@gmail.com last updated on 13/May/20 Commented by prakash jain last updated on 14/May/20 $$\mathrm{English}\:\mathrm{please} \\ $$ Terms of Service Privacy Policy…
Question Number 93569 by kikomssn@gmail.com last updated on 13/May/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28027 by ajfour last updated on 18/Jan/18 Answered by mrW2 last updated on 19/Jan/18 $${radius}\:{of}\:{base}\:{circle}\:={R} \\ $$$${radius}\:{of}\:{disc}\:{in}\:{distance}\:{x}\:{from}\:{the} \\ $$$${base}\:{is}\:{r}=\frac{{h}−{x}}{{h}}×{R}=\left(\mathrm{1}−\frac{{x}}{{h}}\right){R} \\ $$$${mass}\:{of}\:{disc}\:{is}\:{dm}=\rho\pi{r}^{\mathrm{2}} {dx} \\…
Question Number 159085 by ajfour last updated on 12/Nov/21 Answered by mr W last updated on 15/Nov/21 Commented by mr W last updated on 15/Nov/21…
Question Number 27954 by Tinkutara last updated on 17/Jan/18 Commented by Tinkutara last updated on 17/Jan/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 27899 by Tinkutara last updated on 16/Jan/18 Answered by mrW2 last updated on 17/Jan/18 $${let}\:{e}={max}.\:{elongation}\:{of}\:{spring}\:{after}\:{release} \\ $$$${ke}=\mu{m}_{{A}} {g}\:\:\:\:\:…\left({i}\right) \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}{kd}^{\mathrm{2}} −\mu{m}_{{B}} {g}\left({d}+{e}\right)=\frac{\mathrm{1}}{\mathrm{2}}{ke}^{\mathrm{2}} \:\:\:\:…\left({ii}\right)…