Question Number 91167 by mr W last updated on 28/Apr/20 Commented by mr W last updated on 28/Apr/20 $${also} \\ $$ Commented by mr W…
Question Number 90923 by ajfour last updated on 26/Apr/20 Commented by ajfour last updated on 26/Apr/20 $${A}\:{ball}\:{of}\:{mass}\:{m}\:{hits}\:{horizontally} \\ $$$${and}\:{elastically}\:{the}\:{centre}\:{of}\:{a} \\ $$$${hinged}\:{square}\:{plate}\:{of}\:{side}\:{s}\:{and} \\ $$$${mass}\:{M}.\:{Find}\:{velocity}\:{v}\:{of}\:{ball} \\ $$$${juzt}\:{after}\:{impact}.…
Question Number 90819 by ajfour last updated on 26/Apr/20 Commented by ajfour last updated on 26/Apr/20 $${mass}\:{of}\:{rod}\:{is}\:{M},\:{and}\:\alpha=\mathrm{0},\:{but} \\ $$$${rod}\:{rotates}\:{with}\:{constant}\:{angular} \\ $$$${veloity}\:\omega_{\mathrm{0}} \:,\:{then}\:{find}\:{relative}\: \\ $$$${speed}\:{of}\:{small}\:{mass}\:{m}\:{with} \\…
Question Number 90509 by ajfour last updated on 24/Apr/20 Commented by ajfour last updated on 24/Apr/20 $${If}\:{the}\:{brown}\:{hemisphere}\:{is}\:{about} \\ $$$${to}\:{slide},\:{find}\:\theta. \\ $$ Commented by mr W…
Question Number 90331 by ajfour last updated on 22/Apr/20 Commented by ajfour last updated on 22/Apr/20 $${Express}\:{maximum}\:{of}\:{x},\:{in}\:{terms} \\ $$$${of}\:{a},{h},{l},\mu,{g}. \\ $$ Answered by mr W…
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Question Number 155561 by peter frank last updated on 02/Oct/21 Answered by mr W last updated on 02/Oct/21 $${p}_{\mathrm{1}} ={pressure}\:{inside}\:{bubble}\:{at}\:{radius}\:{r} \\ $$$${p}_{\mathrm{2}} ={pressure}\:{inside}\:{bubble}\:{at}\:{radius}\:\mathrm{2}{r} \\ $$$${p}_{\mathrm{1}}…
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Question Number 155381 by ajfour last updated on 29/Sep/21 Commented by mr W last updated on 30/Sep/21 Commented by mr W last updated on 30/Sep/21…
Question Number 155292 by peter frank last updated on 28/Sep/21 Answered by peter frank last updated on 30/Sep/21 $$\mathrm{R}=\mathrm{a}=\frac{\mathrm{v}^{\mathrm{2}} \mathrm{sin}\:\mathrm{2}\theta}{\mathrm{g}}=\frac{\mathrm{2v}^{\mathrm{2}} \mathrm{sin}\:\theta\mathrm{cos}\:\theta}{\mathrm{g}}…\left(\mathrm{i}\right) \\ $$$$\mathrm{H}=\mathrm{x}=\frac{\mathrm{v}^{\mathrm{2}} \mathrm{sin}\:^{\mathrm{2}} \theta}{\mathrm{2g}}…