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Category: Mechanics

Find-the-force-parallel-to-the-slope-required-to-move-a-body-of-mass-2kg-up-a-slope-inclined-at-30-to-the-horizontal-with-an-acceleration-oc-2m-s-2-if-the-frictional-force-is-10N-

Question Number 64751 by necx1 last updated on 21/Jul/19 $${Find}\:{the}\:{force}\:{parallel}\:{to}\:{the}\:{slope} \\ $$$${required}\:{to}\:{move}\:{a}\:{body}\:{of}\:{mass}\:\mathrm{2}{kg} \\ $$$${up}\:{a}\:{slope}\:{inclined}\:{at}\:\mathrm{30}°\:{to}\:{the} \\ $$$${horizontal}\:{with}\:{an}\:{acceleration}\:{oc}\:\mathrm{2}{m}/{s}^{\mathrm{2}} \\ $$$${if}\:{the}\:{frictional}\:{force}\:{is}\:\mathrm{10}{N}. \\ $$ Commented by necx1 last updated…

A-body-of-mass-4kg-is-at-the-point-of-slipping-down-a-plane-which-is-inclined-at-30-to-the-horizontal-What-is-the-force-parallel-to-the-plane-that-will-just-move-it-up-

Question Number 64750 by necx1 last updated on 21/Jul/19 $${A}\:{body}\:{of}\:{mass}\:\mathrm{4}{kg}\:{is}\:{at}\:{the}\:{point}\:{of} \\ $$$${slipping}\:{down}\:{a}\:{plane}\:{which}\:{is} \\ $$$${inclined}\:{at}\:\mathrm{30}°\:{to}\:{the}\:{horizontal}.{What} \\ $$$${is}\:{the}\:{force}\:{parallel}\:{to}\:{the}\:{plane}\:{that} \\ $$$${will}\:{just}\:{move}\:{it}\:{up}? \\ $$ Terms of Service Privacy Policy…

Question-64698

Question Number 64698 by Rio Michael last updated on 20/Jul/19 Commented by Rio Michael last updated on 20/Jul/19 $${the}\:{figure}\:{above}\:{shows}\:{a}\:{wood}\:{of}\:{mass}\:\mathrm{50}{kg}\:{held}\:{by}\:{a}\:{rope}\: \\ $$$${which}\:{is}\:{inclined}\:{at}\:\mathrm{30}°\:{to}\:{the}\:{wood}\:{and}\:{supported}\:{by}\:{a}\:{wall}. \\ $$$${calculate}\:{the}\:{tension}\:{in}\:{the}\:{rope} \\ $$$$\:\:\:\left({take}\:{g}\:=\:\mathrm{10}{ms}^{−\mathrm{2}}…

Calculate-the-energy-loss-when-a-5-kg-object-moving-at-5-ms-1-collides-head-on-with-and-sticks-to-a-stationary-3-kg-object-Answer-3-75-J-I-need-help-How-do-I-arrive-at-this-

Question Number 130066 by Don08q last updated on 22/Jan/21 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{energy}\:\mathrm{loss}\:\mathrm{when}\:\mathrm{a}\:\mathrm{5}\:{kg} \\ $$$$\mathrm{object}\:\mathrm{moving}\:\mathrm{at}\:\mathrm{5}\:{ms}^{−\mathrm{1}} \:\mathrm{collides}\:\mathrm{head} \\ $$$$−\mathrm{on}\:\mathrm{with}\:\mathrm{and}\:\mathrm{sticks}\:\mathrm{to}\:\mathrm{a}\:\mathrm{stationary} \\ $$$$\mathrm{3}\:{kg}\:\mathrm{object}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\boldsymbol{{Answer}}:\:\:\mathrm{3}.\mathrm{75}\:\mathrm{J}\right] \\ $$$$\:{I}\:{need}\:{help}.\:\mathrm{How}\:\mathrm{do}\:\mathrm{I}\:\mathrm{arrive}\:\mathrm{at}\:\mathrm{this} \\ $$$$\:\mathrm{answer}? \\ $$…

Question-129660

Question Number 129660 by ajfour last updated on 17/Jan/21 Commented by ajfour last updated on 17/Jan/21 $${If}\:{a}\:{plank}\:{is}\:{released}\:{in}\:{contact} \\ $$$${with}\:{a}\:{smooth}\:{cylinder}\:{of}\:{radius} \\ $$$${R},\:{at}\:{an}\:{angle}\:\alpha.\:{Find}\:{the}\:{angle} \\ $$$$\theta\:{when}\:{plank}\:{is}\:{about}\:{to}\:{leave} \\ $$$${contact}\:{with}\:{cylinder}.…