Question Number 74418 by peter frank last updated on 24/Nov/19 Answered by ajfour last updated on 24/Nov/19 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\overset{\:^{\overset{{N}} {\nwarrow}} \underset{\underset{{mg}} {\downarrow}} {\mathbb{C}}\rightarrow_{{mv}^{\mathrm{2}} /{R}} } {\diagup}…
Question Number 74415 by Learner-123 last updated on 24/Nov/19 Commented by Learner-123 last updated on 24/Nov/19 $${please}\:{solve}\:{this}\:{by}\:{conservation}\:{of} \\ $$$${energy}. \\ $$ Answered by ajfour last…
Question Number 74308 by Learner-123 last updated on 21/Nov/19 Answered by Tanmay chaudhury last updated on 22/Nov/19 $${P}×\mathrm{2}{R}={I}\alpha \\ $$$$\alpha=\frac{{w}−{w}_{\mathrm{0}} }{{t}} \\ $$$$\frac{{w}−{w}_{\mathrm{0}} }{{t}}=\frac{{P}×\mathrm{2}{R}}{{I}} \\…
Question Number 74274 by Learner-123 last updated on 21/Nov/19 Answered by mr W last updated on 21/Nov/19 $${ring}: \\ $$$${r}=\sqrt{{l}^{\mathrm{2}} −{h}^{\mathrm{2}} } \\ $$$${M}=\mathrm{2}\pi{r}\rho \\…
Question Number 74075 by ajfour last updated on 18/Nov/19 Commented by ajfour last updated on 18/Nov/19 $${To}\:{Tinkutara}\: \\ $$$${I}\:{was}\:{going}\:{to}\:{delete}\:{it}\:{on}\:{second} \\ $$$${thought}\:{but}\:{i}\:{touched}\:{upvote} \\ $$$${and}\:{cannot}\:{delete}\:{it}\:{now}, \\ $$$$\left({please}\:{help}\:{delete}\:{it}.\right)…
Question Number 73910 by Rio Michael last updated on 16/Nov/19 Commented by Rio Michael last updated on 16/Nov/19 $${given}\:{figure}\:\mathrm{1}. \\ $$$${in}\:{which}\:{direction}\:{will}\:{the}\:{reaction}\:{of}\:{at}\:{the} \\ $$$${hinge}\:{be}\:{inclined}. \\ $$$${is}\:{it}\:{to}\:{the}\:{vertical}\:{or}\:{horizontal}?…
Question Number 73451 by Learner-123 last updated on 12/Nov/19 Commented by Learner-123 last updated on 12/Nov/19 $${Please}\:{tell}\:{whether}\:{the}\:{statement}\:{is} \\ $$$${true}\:{or}\:{false}\:.\left({all}\:\mathrm{10}\right). \\ $$ Commented by Learner-123 last…
Question Number 73441 by Learner-123 last updated on 12/Nov/19 Answered by mr W last updated on 12/Nov/19 $$\frac{\mathrm{1}+\mathrm{2}}{\mathrm{1}}=\left(\frac{\mathrm{7}+{d}}{\mathrm{7}}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{d}=\mathrm{7}\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)=\mathrm{5}.\mathrm{12}\:{m} \\ $$$$ \\ $$$${v}_{\mathrm{0}} {t}=\mathrm{7}…
Question Number 73297 by mr W last updated on 10/Nov/19 Commented by mr W last updated on 10/Nov/19 $${a}\:{block}\:{of}\:{mass}\:{m}\:{is}\:{released}\:{at}\:{the} \\ $$$${top}\:{of}\:{a}\:{hemisphere}. \\ $$$${find}\:{the}\:{time}\:{for}\:{the}\:{block}\:{to}\:{hit}\:{the} \\ $$$${ground}\:{and}\:{the}\:{position}\:{of}\:{the}\:{hit}.…
Question Number 73260 by Lontum Hans last updated on 09/Nov/19 Answered by mr W last updated on 09/Nov/19 $${T}_{{max}} ={m}\left(\frac{{v}^{\mathrm{2}} }{{r}}+{g}\right)=\mathrm{8}\left(\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}+\mathrm{10}\right)=\mathrm{224}\:{N} \\ $$$${T}_{{min}} ={m}\left(\frac{{v}^{\mathrm{2}}…