Question Number 137890 by Teli last updated on 07/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 72198 by mr W last updated on 26/Oct/19 Commented by mr W last updated on 26/Oct/19 $${the}\:{small}\:{ball}\:{with}\:{mass}\:{m}\:{and}\:{radius} \\ $$$${r}\:{is}\:{released}\:{at}\:{the}\:{given}\:{position}. \\ $$$${find}\:{the}\:{period}\:{of}\:{the}\:{swing}\:{motion}. \\ $$$${pure}\:{rolling}\:{is}\:{assumed}.…
Question Number 72178 by ajfour last updated on 25/Oct/19 Commented by ajfour last updated on 25/Oct/19 $${If}\:{released}\:{as}\:{shown},\:{in}\:{what} \\ $$$${time}\:{does}\:{the}\:{block}\:{separate} \\ $$$${from}\:{the}\:{hemisphere}? \\ $$ Commented by…
Question Number 72150 by daniyal_ahmad last updated on 25/Oct/19 Commented by daniyal_ahmad last updated on 25/Oct/19 $$\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{any}}\:\boldsymbol{\mathrm{one}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{problem}}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 72108 by ajfour last updated on 24/Oct/19 Answered by Tanmay chaudhury last updated on 24/Oct/19 $${Torque}\:{due}\:{to}\:{mg}\:\:\:\Gamma=\left(\frac{{l}}{\mathrm{2}}−{a}\right){mgsin}\left(\frac{\pi}{\mathrm{2}}+\alpha\right) \\ $$$$\left(\frac{{l}}{\mathrm{2}}−{a}\right){mgcos}\alpha={I}.\beta \\ $$$${calculation}\:{of}\:{I}=\frac{{ml}^{\mathrm{2}} }{\mathrm{12}}+{m}\left(\frac{{l}}{\mathrm{2}}−{a}\right)^{\mathrm{2}} \\ $$$$\theta=\mathrm{0}.{t}+\frac{\mathrm{1}}{\mathrm{2}}\beta{t}^{\mathrm{2}}…
Question Number 137613 by physicstutes last updated on 04/Apr/21 $$\mathrm{Two}\:\mathrm{particles}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{and}\:\mathrm{4}{m}\:\mathrm{are}\:\mathrm{connected}\:\mathrm{by}\:\mathrm{a}\:\mathrm{light}\:\mathrm{inelastic} \\ $$$$\mathrm{string}\:\mathrm{of}\:\mathrm{length}\:\mathrm{3}{a},\:\mathrm{which}\:\mathrm{passes}\:\mathrm{through}\:\mathrm{a}\:\mathrm{small}\:\mathrm{smooth}\:\mathrm{fixed}\:\mathrm{ring}. \\ $$$$\mathrm{The}\:\mathrm{heavier}\:\mathrm{particle}\:\mathrm{hangs}\:\mathrm{at}\:\mathrm{rest}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{2}{a}\:\mathrm{beneath}\:\mathrm{the}\:\mathrm{ring}, \\ $$$$\mathrm{while}\:\mathrm{the}\:\mathrm{lighter}\:\mathrm{particle}\:\mathrm{describes}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{circle}\:\mathrm{with}\:\mathrm{constant} \\ $$$$\mathrm{speed}. \\ $$$$\:\mathrm{Find} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{The}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{below}\:\mathrm{the}\:\mathrm{ring}. \\ $$$$\left(\mathrm{b}\right)\:\mathrm{The}\:\mathrm{angular}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{lighter}\:\mathrm{particle}. \\…
Question Number 72036 by mr W last updated on 23/Oct/19 Commented by mr W last updated on 23/Oct/19 $${the}\:{cup}\:{has}\:{the}\:{shape}\:{of}\:{hemisphere} \\ $$$${with}\:{radius}\:{R}.\:{a}\:{stick}\:{of}\:{mass}\:{m}\:{and} \\ $$$${length}\:{l}\:\left(\mathrm{2}{R}<{l}<\mathrm{4}{R}\right)\:{is}\:{released}\:{at} \\ $$$${blue}\:{position}.\:{there}\:{is}\:{no}\:{friction}…
Question Number 71939 by ajfour last updated on 22/Oct/19 Commented by ajfour last updated on 22/Oct/19 $${Find}\:{v}\:{and}\:{V}\:{in}\:{terms}\:{of}\:{given} \\ $$$${parameters}.\:{coefficient}\:{of} \\ $$$${restitution}\:{is}\:{e}\:{and}\:{the}\:{plane}\:{is} \\ $$$${frictionless}\:{horizontal}\:{ground}. \\ $$…
Question Number 137210 by BHOOPENDRA last updated on 31/Mar/21 Answered by mr W last updated on 31/Mar/21 $${a}=\frac{{F}}{{m}+{M}} \\ $$$${F}_{\mathrm{1}} ={Ma}=\frac{{MF}}{{m}+{M}} \\ $$ Terms of…
Question Number 71643 by ajfour last updated on 18/Oct/19 Commented by ajfour last updated on 23/Oct/19 $${Assuming}\:{perfectly}\:{inelastic} \\ $$$${collision}\:{takes}\:{place}\:{and}\:{sphere} \\ $$$${climbs}\:{up}\:{the}\:{embankment}. \\ $$$${Find}\:{u}_{{min}} \:{for}\:{this}\:{to}\:{be}\:{possible}. \\…