Question Number 137986 by ajfour last updated on 08/Apr/21 Commented by ajfour last updated on 08/Apr/21 $${Find}\:{maximum}\:{speed}\:{gained} \\ $$$${by}\:{cylinder}\:{if}\:{motion}\:{is} \\ $$$${initiated}.\:{Bottom}\:{corner}\:{is} \\ $$$${hinged}\:{to}\:{ground}. \\ $$…
Question Number 72435 by ajfour last updated on 28/Oct/19 Commented by ajfour last updated on 28/Oct/19 $${The}\:{parabolic}\:{surface}\:{is}\:{y}={x}^{\mathrm{2}} . \\ $$$${Find}\:{time}\:{period}\:{of}\:{small}\: \\ $$$${oscillations}\:{of}\:{the}\:{rod}.\: \\ $$$$\left({the}\:{end}\:{wheels}\:{are}\:{small}\right). \\…
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Question Number 72198 by mr W last updated on 26/Oct/19 Commented by mr W last updated on 26/Oct/19 $${the}\:{small}\:{ball}\:{with}\:{mass}\:{m}\:{and}\:{radius} \\ $$$${r}\:{is}\:{released}\:{at}\:{the}\:{given}\:{position}. \\ $$$${find}\:{the}\:{period}\:{of}\:{the}\:{swing}\:{motion}. \\ $$$${pure}\:{rolling}\:{is}\:{assumed}.…
Question Number 72178 by ajfour last updated on 25/Oct/19 Commented by ajfour last updated on 25/Oct/19 $${If}\:{released}\:{as}\:{shown},\:{in}\:{what} \\ $$$${time}\:{does}\:{the}\:{block}\:{separate} \\ $$$${from}\:{the}\:{hemisphere}? \\ $$ Commented by…
Question Number 72150 by daniyal_ahmad last updated on 25/Oct/19 Commented by daniyal_ahmad last updated on 25/Oct/19 $$\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{any}}\:\boldsymbol{\mathrm{one}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{problem}}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 72108 by ajfour last updated on 24/Oct/19 Answered by Tanmay chaudhury last updated on 24/Oct/19 $${Torque}\:{due}\:{to}\:{mg}\:\:\:\Gamma=\left(\frac{{l}}{\mathrm{2}}−{a}\right){mgsin}\left(\frac{\pi}{\mathrm{2}}+\alpha\right) \\ $$$$\left(\frac{{l}}{\mathrm{2}}−{a}\right){mgcos}\alpha={I}.\beta \\ $$$${calculation}\:{of}\:{I}=\frac{{ml}^{\mathrm{2}} }{\mathrm{12}}+{m}\left(\frac{{l}}{\mathrm{2}}−{a}\right)^{\mathrm{2}} \\ $$$$\theta=\mathrm{0}.{t}+\frac{\mathrm{1}}{\mathrm{2}}\beta{t}^{\mathrm{2}}…
Question Number 137613 by physicstutes last updated on 04/Apr/21 $$\mathrm{Two}\:\mathrm{particles}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{and}\:\mathrm{4}{m}\:\mathrm{are}\:\mathrm{connected}\:\mathrm{by}\:\mathrm{a}\:\mathrm{light}\:\mathrm{inelastic} \\ $$$$\mathrm{string}\:\mathrm{of}\:\mathrm{length}\:\mathrm{3}{a},\:\mathrm{which}\:\mathrm{passes}\:\mathrm{through}\:\mathrm{a}\:\mathrm{small}\:\mathrm{smooth}\:\mathrm{fixed}\:\mathrm{ring}. \\ $$$$\mathrm{The}\:\mathrm{heavier}\:\mathrm{particle}\:\mathrm{hangs}\:\mathrm{at}\:\mathrm{rest}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{2}{a}\:\mathrm{beneath}\:\mathrm{the}\:\mathrm{ring}, \\ $$$$\mathrm{while}\:\mathrm{the}\:\mathrm{lighter}\:\mathrm{particle}\:\mathrm{describes}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{circle}\:\mathrm{with}\:\mathrm{constant} \\ $$$$\mathrm{speed}. \\ $$$$\:\mathrm{Find} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{The}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{below}\:\mathrm{the}\:\mathrm{ring}. \\ $$$$\left(\mathrm{b}\right)\:\mathrm{The}\:\mathrm{angular}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{lighter}\:\mathrm{particle}. \\…
Question Number 72036 by mr W last updated on 23/Oct/19 Commented by mr W last updated on 23/Oct/19 $${the}\:{cup}\:{has}\:{the}\:{shape}\:{of}\:{hemisphere} \\ $$$${with}\:{radius}\:{R}.\:{a}\:{stick}\:{of}\:{mass}\:{m}\:{and} \\ $$$${length}\:{l}\:\left(\mathrm{2}{R}<{l}<\mathrm{4}{R}\right)\:{is}\:{released}\:{at} \\ $$$${blue}\:{position}.\:{there}\:{is}\:{no}\:{friction}…