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Category: Mechanics

Question-137148

Question Number 137148 by nadovic last updated on 30/Mar/21 Answered by ajfour last updated on 30/Mar/21 $$\left(\mathrm{3}{kg}\right)\left(\mathrm{4}{m}/{s}\right)=\left(\mathrm{3}{kg}\right){v}+\left(\mathrm{5}{kg}\right){V} \\ $$$$\left.{V}−{v}=\left(\mathrm{0}.\mathrm{6}\right)\left(\mathrm{4}{m}/{s}\right)\:\:\:\right\}×\mathrm{3} \\ $$$$\mathrm{3}{v}+\mathrm{5}{V}=\mathrm{12}{m}/{s} \\ $$$${Adding} \\ $$$$\mathrm{8}{V}=\mathrm{19}.\mathrm{2}{m}/{s}…

Question-71421

Question Number 71421 by ajfour last updated on 15/Oct/19 Commented by ajfour last updated on 15/Oct/19 $${Find}\:{speed}\:{of}\:{sphere}\:{as}\:{it}\:{rolls} \\ $$$${down}\:{the}\:{wedge},\:{and}\:{is}\:{about}\:{to} \\ $$$${touch}\:{the}\:{ground}.\:{Also}\:{find}\:{the} \\ $$$${least}\:{coefficient}\:{of}\:{friction}, \\ $$$${so}\:{that}\:{sphere}\:{comes}\:{rolling}\:{all}…