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Category: Mechanics

Question-136136

Question Number 136136 by BHOOPENDRA last updated on 19/Mar/21 Answered by mr W last updated on 19/Mar/21 $${a}=\frac{{F}}{{m}}=\frac{\mathrm{150}}{\mathrm{10}}=\mathrm{15}\:{m}/{s}^{\mathrm{2}} \\ $$$${at}\:{t}=\mathrm{12}\:{s}: \\ $$$${v}={at}=\mathrm{15}×\mathrm{12}=\mathrm{180}\:{m}/{s} \\ $$$${s}=\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{15}×\mathrm{12}^{\mathrm{2}}…

Question-70543

Question Number 70543 by mr W last updated on 05/Oct/19 Commented by mr W last updated on 05/Oct/19 $${a}\:{semi}−{cylinder}\:{with}\:{radius}\:{R}\:{and} \\ $$$${mass}\:{M}\:{rests}\:{on}\:{a}\:{rough}\:{table}\:{as}\:{shown}. \\ $$$${when}\:{a}\:{small}\:{impulse}\:{is}\:{given}\:{to}\:{the} \\ $$$${semi}−{cylinder},\:{it}\:{begins}\:{to}\:{oscillate}.…

Question-70423

Question Number 70423 by ajfour last updated on 04/Oct/19 Commented by ajfour last updated on 04/Oct/19 $${Within}\:{a}\:{hollow}\:{sphere},\:{mass} \\ $$$${M}_{\mathrm{0}} \:,\:{radius}\:{R},\:{rests}\:{two}\:{smaller} \\ $$$${spheres}\:{masses},\:{M}\:{and}\:{m},\:{radii} \\ $$$${b},\:{a}\:,\:{respectively}.\:{Find}\:{equilibrium} \\…

At-what-speed-should-a-basket-ball-player-project-a-ball-from-a-height-of-2-1-m-above-the-ground-at-an-angle-of-38-to-the-horizontal-so-that-it-just-passes-through-a-basket-ball-net-which-is-at-a-ho

Question Number 135618 by physicstutes last updated on 14/Mar/21 $$\:\mathrm{At}\:\mathrm{what}\:\mathrm{speed}\:\mathrm{should}\:\mathrm{a}\:\mathrm{basket}\:\mathrm{ball}\:\mathrm{player}\:\mathrm{project}\:\mathrm{a}\:\mathrm{ball}\:\mathrm{from}\:\mathrm{a}\:\mathrm{height} \\ $$$$\mathrm{of}\:\mathrm{2}.\mathrm{1}\:\mathrm{m} \\ $$$$\mathrm{above}\:\mathrm{the}\:\mathrm{ground}\:\mathrm{at}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{38}° \\ $$$$\mathrm{to}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{so}\:\mathrm{that}\:\mathrm{it}\:\mathrm{just}\:\mathrm{passes}\:\mathrm{through}\:\mathrm{a}\:\mathrm{basket}\:\mathrm{ball}\:\mathrm{net}\:\mathrm{which} \\ $$$$\mathrm{is}\:\mathrm{at}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{5}\:\mathrm{m}\:\mathrm{from}\:\mathrm{the}\:\mathrm{initial} \\ $$$$\mathrm{position}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ball}\:\mathrm{and}\:\mathrm{3}\:\mathrm{m}\:\mathrm{above}\:\mathrm{the}\:\mathrm{playground}.\:\mathrm{at}\:\mathrm{determine}\:\mathrm{the}\:\mathrm{balls} \\ $$$$\mathrm{maximum}\:\mathrm{height}\:\mathrm{above}\:\mathrm{the}\:\mathrm{ground}. \\ $$ Answered…