Question Number 69827 by Learner-123 last updated on 28/Sep/19 $${The}\:{acceleration}\:{of}\:{a}\:{particle}\:{moving} \\ $$$${in}\:{a}\:{straight}\:{line}\:{is}\:{defined}\:{as}\:{a}=\mathrm{6}{t}−\mathrm{20} \\ $$$${m}/{s}^{\mathrm{2}} ,\:{where}\:{t}\:{is}\:{in}\:{seconds}.\:{Knowing} \\ $$$${that}\:{s}=\mathrm{0}{m}\:{when}\:{t}=\mathrm{3}{s}\:{and}\:{that}\:{t}=\mathrm{5}{sec} \\ $$$${when}\:{v}=\mathrm{2}{m}/{s}.\:{Determine}\:{the}\:{total} \\ $$$${distance}\:{travelled}\:{when}\:{t}=\mathrm{11}{s}. \\ $$ Answered by…
Question Number 135350 by muhammadabdallah last updated on 12/Mar/21 Commented by Dwaipayan Shikari last updated on 12/Mar/21 $${What}\:{is}\:\eta\:\:,\:{a}\:{and}\:\Pi\:{here}? \\ $$ Terms of Service Privacy Policy…
Question Number 69754 by jagannath19 last updated on 27/Sep/19 Commented by jagannath19 last updated on 27/Sep/19 $${please}\:{answer}\:{with}\:{explanation} \\ $$ Commented by Rio Michael last updated…
Question Number 69746 by jagannath19 last updated on 27/Sep/19 Commented by jagannath19 last updated on 27/Sep/19 $${answer}\:{with}\:{explanation} \\ $$ Answered by mr W last updated…
Question Number 135213 by mr W last updated on 11/Mar/21 Commented by mr W last updated on 11/Mar/21 $${if}\:{the}\:{truck}\:{can}\:{start}\:{with}\:{an} \\ $$$${acceleration}\:{a},\:{find}\:{the}\:{friction} \\ $$$${coefficient}\:{between}\:{tires}\:{and}\:{ground}. \\ $$…
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Question Number 135101 by BHOOPENDRA last updated on 10/Mar/21 Commented by BHOOPENDRA last updated on 10/Mar/21 $${find}\:{moment}\:{of}\:{inertia}? \\ $$ Commented by mr W last updated…
Question Number 69429 by Learner-123 last updated on 23/Sep/19 Commented by Learner-123 last updated on 23/Sep/19 $${v}_{{a}} =\:\mathrm{162}{km}/{h}\:\left(\nwarrow\right) \\ $$$${v}_{{b}} =\mathrm{144}{km}/{h}\:\left(\searrow\right) \\ $$ Commented by…
Question Number 69398 by Tony Lin last updated on 23/Sep/19 Commented by Tony Lin last updated on 23/Sep/19 $${Solve}\:\mathrm{53}.\&\mathrm{55}. \\ $$ Answered by mr W…
Question Number 134768 by abdurehime last updated on 07/Mar/21 Commented by abdurehime last updated on 07/Mar/21 $$\mathrm{be}\:\mathrm{fast}\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{in}\:\mathrm{10}\:\mathrm{min} \\ $$ Commented by mr W last updated…