Question Number 68510 by oyemi kemewari last updated on 12/Sep/19 Answered by mr W last updated on 14/Sep/19 $${v}=\sqrt{\mathrm{2}{gh}} \\ $$$${base}\:{area}\:{of}\:{tanks}={A}=\mathrm{1}\:{ft}^{\mathrm{2}} \\ $$$${A}\frac{{dh}}{\mathrm{2}}=−\frac{\pi{d}^{\mathrm{2}} }{\mathrm{4}}{vdt} \\…
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Question Number 68487 by mr W last updated on 11/Sep/19 Commented by mr W last updated on 11/Sep/19 $${rod}\:{AB}\:{has}\:{length}\:{b}\:{and}\:{mass}\:{M}, \\ $$$${rope}\:{BC}\:{has}\:{length}\:{l}\:{and}\:{mass}\:{m}, \\ $$$${the}\:{friction}\:{between}\:{rod}\:{and}\:{ground} \\ $$$${is}\:{sufficient},\:{such}\:{that}\:{point}\:{A}\:{can}…
Question Number 68451 by mr W last updated on 10/Sep/19 Commented by mr W last updated on 11/Sep/19 $${if}\:{M}=\mathrm{0},\:{the}\:{block}\:{m}\:{just}\:{has}\:{free} \\ $$$${fall},\:{therefore}\:{T}=\sqrt{\mathrm{2}{gh}}=\sqrt{\mathrm{2}{gR}}. \\ $$ Commented by…
Question Number 68418 by necxxx last updated on 10/Sep/19 Commented by necxxx last updated on 10/Sep/19 $${The}\:{UDL}\:{is}\:\mathrm{2}.\mathrm{5}{KN}/{m}.\:{The}\:{first}\:{point} \\ $$$${load}\:{is}\:\mathrm{35}{KN}.\:{I}'{ve}\:{tried}\:{solving}\:{but}\:{I} \\ $$$${encountered}\:{some}\:{issues}\:{with}\:{the}\:{diagram}. \\ $$$${I}'{ll}\:{be}\:{really}\:{grateful}\:{to}\:{get}\:{this}\:{solved} \\ $$$${with}\:{the}\:{possible}\:{diagrams}.…
Question Number 68342 by Tony Lin last updated on 09/Sep/19 Commented by Tony Lin last updated on 09/Sep/19 $${when}\:{m}\:{slide}\:{to}\:{the}\:{bottom} \\ $$$${if}\:{there}\:{is}\:{no}\:{fraction} \\ $$$${find}\:{v}_{{m}} \&{v}_{{M}} \\…
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Question Number 68222 by necxxx last updated on 07/Sep/19 $${Sketch}\:{the}\:{shear}\:{and}\:{moment}\:{diagrams} \\ $$$${of}\:{a}\:{simply}\:{supported}\:{beam}\:{of}\:\mathrm{6}{m}.{The} \\ $$$${load}\:{on}\:{the}\:{beam}\:{consists}\:{of}\:{UDL}\:{of} \\ $$$$\mathrm{15}{KN}/{m}\:{over}\:{the}\:{left}\:{half}\:{of}\:{the}\:{span}. \\ $$$$ \\ $$ Commented by necxxx last updated…
Question Number 133730 by mr W last updated on 24/Feb/21 Commented by mr W last updated on 23/Feb/21 $${as}\:{Q}\mathrm{133275},\:{but}\:{with}\:{coefficient}\:{of} \\ $$$${restitution}\:\boldsymbol{{e}}\:{for}\:{the}\:{impacts}. \\ $$ Commented by…
Question Number 68073 by necxxx last updated on 04/Sep/19 $$\:{A}\:{straight}\:{rod}\:{AB}\:{which}\:{is}\:\mathrm{60}{cm}\:{long},{is} \\ $$$${in}\:{equilibrum}\:{when}\:{horizontal}\:{and} \\ $$$${supported}\:{at}\:{a}\:{point}\:{C},\mathrm{10}{cm}\:{from}\:{A}, \\ $$$${with}\:{masses}\:\mathrm{6}{kg}\:{and}\:\mathrm{1}{kg}\:{attached}\:{to}\:{the} \\ $$$${rod}\:{at}\:{A}\:{and}\:{B}\:{respectively}.{It}\:{is}\:{also}\:{in} \\ $$$${equilibrum}\:{and}\:{horizontal}\:{when}\: \\ $$$${supported}\:{at}\:{another}\:{pivott}\:{at}\:{its}\:{mid}- \\ $$$${point},{with}\:{masses}\:{of}\:\mathrm{2}{kg}\:{and}\:\mathrm{5}{kg}\: \\…