Question Number 61867 by readone97 last updated on 10/Jun/19 $$\:{a}\:{player}\:{kicked}\:{a}\:{football}\:{at}\:{angel}\:\mathrm{30}\:{with}\:{the}\:{ground}\:{towards}\:{an}\:{empty}\:{goal}\:{post}\:{of}\:{hegith}\:\mathrm{3}.\mathrm{4}{m}\:{the}\:{ball}\:{hits}\:{the}\:{crossbar}\:{of}\:{the}\:{goal}\:{post}\:\mathrm{30}{m}\:{away}\:{from}\:{where}\:{the}\:{ball}\:{was}\:{kicked}.\:{Take}\:{g}=\mathrm{9}.\mathrm{8}{m}/{s}.\:{Find}\:{the}\:{intial}\:{velocity}\:{u}\:{of}\:{the}\:{ball}?.{What}\:{is}\:{time}\:{taken}\:{for}\:{the}\:{ball}\:{to}\:{hit}\:{the}\:{crossbar}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192540 by peter frank last updated on 20/May/23 Commented by mr W last updated on 17/Jun/23 $${why}\:{did}\:{you}\:{repeat}\:{the}\:{same}\:{question} \\ $$$${Q}#\mathrm{178890}? \\ $$ Terms of…
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Question Number 126773 by Ar Brandon last updated on 24/Dec/20 Answered by Dwaipayan Shikari last updated on 24/Dec/20 $$\overset{\rightarrow} {{A}}+\overset{\rightarrow} {{B}}+\overset{\rightarrow} {{C}}=\mathrm{0}\hat {{i}}+\hat {{j}}+\mathrm{0}\hat {{k}}…
Question Number 61205 by necx1 last updated on 30/May/19 $${A}\:{cubical}\:{block}\:{of}\:{ice}\:{of}\:{mass}\:{m}\:{and} \\ $$$${edge}\:{L}\:{is}\:{placed}\:{in}\:{a}\:{large}\:{tray}\:{of}\:{mass} \\ $$$${M}.{If}\:{the}\:{ice}\:{block}\:{melts},{how}\:{far}\:{does} \\ $$$${the}\:{centre}\:{of}\:{mass}\:{of}\:{the}\:{system}\:“{ice}\:+\:{tray}'' \\ $$$${come}\:{down}\:? \\ $$$$ \\ $$$$\left.{a}\left.\right)\left.\frac{{ml}}{{m}+{M}}\left.\:\:{b}\right)\frac{\mathrm{2}{ml}}{{m}+{M}}\:\:{c}\right)\frac{{ml}}{\mathrm{2}\left({m}+{M}\right)}\:\:{d}\right){none} \\ $$ Commented…
Question Number 126616 by Khalmohmmad last updated on 22/Dec/20 $${A}=\left({n}−\mathrm{10}\right)×\left({n}−\mathrm{10}\right) \\ $$$${det}\left({A}\right)=?\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 126603 by Ar Brandon last updated on 22/Dec/20 $$\mathrm{If}\:\mathrm{there}\:\mathrm{is}\:\mathrm{a}\:\mathrm{positive}\:\mathrm{error}\:\mathrm{in}\:\mathrm{the}\:\mathrm{measurement} \\ $$$$\mathrm{of}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{a}\:\mathrm{body},\:\mathrm{then}\:\mathrm{the}\:\mathrm{error}\:\mathrm{in}\:\mathrm{the}\:\mathrm{measure}- \\ $$$$\mathrm{ment}\:\mathrm{of}\:\mathrm{kinetic}\:\mathrm{energy}\:\mathrm{is} \\ $$ Answered by Olaf last updated on 22/Dec/20 $$\mathrm{E}\:=\:\frac{\mathrm{1}}{\mathrm{2}}{mv}^{\mathrm{2}}…
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Question Number 191868 by Spillover last updated on 02/May/23 $${A}\:{particle}\:{of}\:{mass}\:{m}\:{moves}\:{under}\:{the}\:{central} \\ $$$${repulsive}\:{force}\:\frac{{mb}}{{r}^{\mathrm{3}} }\:\:{and}\:{is}\:{initially}\:{moving} \\ $$$${at}\:{a}\:{distance}\:'{a}'\:\:{from}\:{the}\:{origin}\:{of}\:\:{a}\:{force} \\ $$$${with}\:{velocity}\:\:'{v}'\:{at}\:{right}\:{angle}\:{to}\:\:'{a}'. \\ $$$${show}\:{that}\:\:\: \\ $$$$\:\:\:\:\:{r}\mathrm{cos}\:{p}\theta={a}\:\:{where}\:{p}\:=\frac{{b}}{{a}^{\mathrm{2}} {v}^{\mathrm{2}} }+\mathrm{1}. \\ $$$$…