Question Number 69429 by Learner-123 last updated on 23/Sep/19 Commented by Learner-123 last updated on 23/Sep/19 $${v}_{{a}} =\:\mathrm{162}{km}/{h}\:\left(\nwarrow\right) \\ $$$${v}_{{b}} =\mathrm{144}{km}/{h}\:\left(\searrow\right) \\ $$ Commented by…
Question Number 69398 by Tony Lin last updated on 23/Sep/19 Commented by Tony Lin last updated on 23/Sep/19 $${Solve}\:\mathrm{53}.\&\mathrm{55}. \\ $$ Answered by mr W…
Question Number 134768 by abdurehime last updated on 07/Mar/21 Commented by abdurehime last updated on 07/Mar/21 $$\mathrm{be}\:\mathrm{fast}\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{in}\:\mathrm{10}\:\mathrm{min} \\ $$ Commented by mr W last updated…
Question Number 134769 by abdurehime last updated on 07/Mar/21 Commented by abdurehime last updated on 07/Mar/21 $$\mathrm{please}\:\mathrm{be}?\mathrm{fast} \\ $$ Commented by john_santu last updated on…
Question Number 134770 by abdurehime last updated on 07/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 69183 by Tony Lin last updated on 21/Sep/19 Commented by Tony Lin last updated on 21/Sep/19 $$\mathrm{49}.\:{m}_{\mathrm{1}} {g}=\left({m}_{\mathrm{1}} +{m}_{\mathrm{2}} \right){a} \\ $$$$\Rightarrow{a}=\frac{{m}_{\mathrm{1}} {g}}{{m}_{\mathrm{1}}…
Question Number 134678 by mr W last updated on 07/Mar/21 Commented by mr W last updated on 06/Mar/21 $${attempt}\:{to}\:{solve}\:{Q}\mathrm{134376} \\ $$ Commented by mr W…
Question Number 69045 by jagannath19 last updated on 18/Sep/19 Answered by Rio Michael last updated on 18/Sep/19 $${F}_{{net}} =\:\mathrm{100}{cos}\mathrm{53}° \\ $$$${ma}\:\approx\:\mathrm{60} \\ $$$$\mathrm{2}\left({a}\right)\:=\:\mathrm{60} \\ $$$${a}\:=\:\mathrm{30}{m}/{s}^{\mathrm{2}}…
Question Number 134376 by mr W last updated on 02/Mar/21 Commented by mr W last updated on 06/Mar/21 $${a}\:{solid}\:{cone}\:{of}\:{mass}\:{m}\:{is}\:{released} \\ $$$${from}\:{rest}\:{at}\:{the}\:{horizontal}\:{position} \\ $$$${on}\:{a}\:{inclined}\:{plane}\:{as}\:{shown}.\:{the}\:{cone} \\ $$$${can}\:{only}\:{roll}\:{on}\:{the}\:{plane}.\:{find}\:{the}…
Question Number 68714 by Learner-123 last updated on 15/Sep/19 Answered by mr W last updated on 15/Sep/19 $${acceleration}\:{of}\:{object}\:{C}=\frac{\mathrm{1}.\mathrm{2}}{\mathrm{2}}=\mathrm{0}.\mathrm{6}{m}/{s}^{\mathrm{2}} \\ $$$${force}\:{in}\:{cable}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{375}×\frac{\mathrm{10}+\mathrm{0}.\mathrm{6}}{\mathrm{10}}=\mathrm{198}.\mathrm{75}\:{N} \\ $$$${power}\:{input}=\frac{\mathrm{198}.\mathrm{75}×\mathrm{0}.\mathrm{6}}{\mathrm{0}.\mathrm{85}}=\mathrm{140}.\mathrm{3}\:{watt} \\ $$ Commented…