Question Number 181253 by sciencestudent last updated on 23/Nov/22 $${define}\:{microscopic}\:{and}\:{macroscopic} \\ $$$${with}\:{one}\:{one}\:{example}. \\ $$ Commented by sciencestudent last updated on 24/Nov/22 $${no}\:{one}\:{ans}\:{without}\:{i}\:{have}\:{to}\:{request}\:{you} \\ $$$${please}\:{ans}\:{me}! \\…
Question Number 113829 by Study last updated on 15/Sep/20 $${what}\:{is}\:{the}\:{darcy}\:{formula}\:{for} \\ $$$${laminar}\:{flow}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 45748 by rahul 19 last updated on 16/Oct/18 Commented by rahul 19 last updated on 16/Oct/18 $${Ans}.\:\rightarrow\:\left({b}\right). \\ $$ Terms of Service Privacy…
Question Number 45747 by rahul 19 last updated on 16/Oct/18 Answered by ajfour last updated on 16/Oct/18 $$\bar {{p}}_{\mathrm{1}{cm}} =\:{m}\left(\frac{\bar {{p}}_{\mathrm{1}} +\bar {{p}}_{\mathrm{2}} }{\mathrm{2}{m}}−\frac{\bar {{p}}_{\mathrm{1}}…
Question Number 45746 by rahul 19 last updated on 16/Oct/18 Commented by rahul 19 last updated on 16/Oct/18 $${Ans}.\:{is}\:\left({c}\right)\:! \\ $$$${Why}\:\left({a}\right),\left({b}\right)\:{are}\:{wrong}? \\ $$ Terms of…
Question Number 45646 by rahul 19 last updated on 15/Oct/18 $${According}\:{to}\:{relativistic}\:{theory}, \\ $$$${E}^{\mathrm{2}} =\:{p}^{\mathrm{2}} {c}^{\mathrm{2}} +{m}_{\mathrm{0}} ^{\mathrm{2}} {c}^{\mathrm{4}} \:{where}\:{m}_{\mathrm{0}} \:{is}\:{rest}\:{mass}. \\ $$$${For}\:{photon}\:{E}=\:{pc}… \\ $$$$\left({m}_{\mathrm{0}} =\mathrm{0}\:{for}\:{photon}\right)…
Question Number 45539 by rahul 19 last updated on 14/Oct/18 Commented by rahul 19 last updated on 14/Oct/18 $${Ans}:\:\frac{{I}\pi{R}^{\mathrm{2}} }{{c}}\:{where}\:{c}={speed}\:{of}\:{light}. \\ $$ Commented by tanmay.chaudhury50@gmail.com…
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Question Number 41373 by Necxx last updated on 06/Aug/18 $${when}\:{uranium}-\mathrm{235}\:{undergoes}\: \\ $$$${nuclear}\:{fission},\mathrm{0}.\mathrm{01\%}\:{of}\:{its}\:{mass} \\ $$$${is}\:{converted}\:{to}\:{energy}.\left({a}\right){Calculate} \\ $$$${the}\:{energy}\:{released}\:{when}\:\mathrm{1}{gm}\:{of} \\ $$$${Uranium}-\mathrm{235}\:{undergoes}\:{nuclear} \\ $$$${fission}.\left({b}\right){What}\:{is}\:{the}\:{amount}\:{of} \\ $$$${uranium}-\mathrm{235}\:{that}\:{will}\:{undergo} \\ $$$${nuclear}\:{fission}\:{reaction}\:{every}\:{hour} \\…
Question Number 41371 by Necxx last updated on 06/Aug/18 $${Calculate}\:{the}\:{amount}\:{of}\:{energy}\circledast \\ $$$${released}\:{when}\:{carbon}-\mathrm{12}\:{nucleus} \\ $$$${is}\:{formed}\:{by}\:{bringing}\:\mathrm{6}\:{neutrons} \\ $$$${and}\:\mathrm{6}\:{protons}\:{together}. \\ $$ Commented by Necxx last updated on 06/Aug/18…