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Question Number 154554 by peter frank last updated on 19/Sep/21 Commented by peter frank last updated on 19/Sep/21 $$\:\:_{\mathrm{2}} ^{\mathrm{3}} \mathrm{He}=\mathrm{3}.\mathrm{01664U} \\ $$ Answered by…
Question Number 152652 by Study last updated on 30/Aug/21 Commented by mr W last updated on 30/Aug/21 $${have}\:{you}\:{machine}\:{translated}\:{this} \\ $$$${question}\:{from}\:{an}\:{other}\:{language}? \\ $$ Terms of Service…
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Question Number 139002 by BHOOPENDRA last updated on 21/Apr/21 Commented by Dwaipayan Shikari last updated on 22/Apr/21 $${Probability}\:\:\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} \mid\Psi\left({x}\right)\mid^{\mathrm{2}} {dx}=\mathrm{1} \\ $$$$=\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} {A}^{\mathrm{2}}…
Question Number 137429 by physicstutes last updated on 02/Apr/21 $$\mathrm{A}\:\mathrm{nuclide}\:_{\mathrm{81}} ^{\mathrm{210}} {X}\:\mathrm{decays}\:\mathrm{to}\:\mathrm{another}\:\mathrm{nuclide}\:_{\mathrm{80}} ^{{A}} {Y}\:\mathrm{in}\: \\ $$$$\mathrm{four}\:\mathrm{successive}\:\mathrm{radioactive}\:\mathrm{decays}.\:\mathrm{Each}\:\mathrm{decay} \\ $$$$\mathrm{involves}\:\mathrm{the}\:\mathrm{emmision}\:\mathrm{of}\:\mathrm{either}\:\mathrm{an}\:\mathrm{alpha}\:\mathrm{particle} \\ $$$$\mathrm{or}\:\mathrm{a}\:\mathrm{beta}\:\mathrm{particle}.\:\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:{A}\:\mathrm{is}: \\ $$$$\mathrm{A}.\:\mathrm{120}\:\:\:\:\:\:\:\:\:\:\:\mathrm{B}.\:\mathrm{206} \\ $$$$\mathrm{C}.\:\mathrm{208}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{D}.\:\mathrm{212} \\…
Question Number 66106 by Umar last updated on 09/Aug/19 $$\mathrm{In}\:\mathrm{an}\:\mathrm{electrolysis}\:\mathrm{experiment},\:\mathrm{the}\:\mathrm{ammeter} \\ $$$$\mathrm{records}\:\mathrm{a}\:\mathrm{steady}\:\mathrm{current}\:\mathrm{of}\:\mathrm{1A}.\:\mathrm{The}\:\mathrm{mass} \\ $$$$\mathrm{of}\:\mathrm{copper}\:\mathrm{deposited}\:\mathrm{in}\:\mathrm{30minutes}\:\mathrm{is}\:\mathrm{0}.\mathrm{66g}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{error}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ammeter}\:\mathrm{reading}. \\ $$$$\:\:\:\mathrm{the}\:\mathrm{electrical}\:\mathrm{equivalent}\:\mathrm{of}\:\mathrm{cu}\:\mathrm{is}\:\mathrm{3}.\mathrm{3}×\mathrm{10}^{−\mathrm{4}} \mathrm{g}/\mathrm{C}. \\ $$ Terms of Service Privacy…