Category: Oscillation and Waves

Question Number 140870 by jlewis last updated on 13/May/21 $$O\mathrm{cean}\mathrm{waves}\mathrm{are}\mathrm{observed}\mathrm{to}$$$$\mathrm{travel}\mathrm{along}\mathrm{the}\mathrm{water}\mathrm{surface}$$$$\mathrm{during}\mathrm{a}\mathrm{developing}\mathrm{storm}.$$$$\mathrm{A}\mathrm{Coast}\mathrm{Guard}\mathrm{weather}\mathrm{station}$$$$\mathrm{observes}\mathrm{that}\mathrm{there}\mathrm{is}\mathrm{a}\mathrm{vertical}$$$$\mathrm{distance}\mathrm{from}\mathrm{high}\mathrm{point}\mathrm{to}\mathrm{low}$$$$\mathrm{point}\mathrm{of}4.6\mathrm{meters}\mathrm{and}\mathrm{horizontal}$$$$\mathrm{distance}\:\mathrm{of}\:\mathrm{8}.\mathrm{6}\:\mathrm{meters}\:\mathrm{between}\: \…

Question Number 73111 by oyemi kemewari last updated on 06/Nov/19 Answered by mr W last updated on 07/Nov/19 $$5=\frac{1}{2}{gt}^2$$$$\Rightarrow t=10s$$$$horizontaldistance=0.8\times 10=8m$$…

Question Number 132265 by Salman_Abir last updated on 12/Feb/21 Answered by physicstutes last updated on 12/Feb/21 $$\mathrm{m}=4\mathrm{kg},k=100{\mathrm{Nm}}^{-1}$$$$T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{4}{100}}$$$$\Rightarrow T=\frac{4\pi }{25}\mathrm{s}$$$$f=\frac{1}{T}=\frac{25}{4\pi }\mathrm{Hz}$$$${T}\:=\:\frac{\mathrm{2}\pi}{\omega}\:\Rightarrow\:\omega\:=\:\frac{\mathrm{2}\pi}{{T}}\:\:=\:\mathrm{2}\pi\:.\:\frac{\mathrm{25}}{\mathrm{4}\pi}\:=\:\frac{\mathrm{25}}{\mathrm{2}}\:\mathrm{rad}/\mathrm{s}…