Question Number 171044 by sciencestudent last updated on 06/Jun/22 $${Is}\:{the}\:{Light}\:{a}\:{matter}? \\ $$ Commented by mr W last updated on 06/Jun/22 $${does}\:{it}\:{matter}\:{if}\:{it}'{s}\:{not}\:{a}\:{matter}? \\ $$ Commented by…
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Question Number 35267 by Tinkutara last updated on 17/May/18 Answered by ajfour last updated on 17/May/18 $${q}=\left(\pi{r}_{\mathrm{0}} ^{\mathrm{2}} \right){v}_{\mathrm{0}} =\left(\pi{r}^{\mathrm{2}} \right){v} \\ $$$${v}^{\mathrm{2}} ={v}_{\mathrm{0}} ^{\mathrm{2}}…
Question Number 35124 by Tinkutara last updated on 15/May/18 Commented by Tinkutara last updated on 15/May/18 $${It}\:{contains}\:{no}\:\alpha? \\ $$ Commented by Tinkutara last updated on…
Question Number 34762 by Tinkutara last updated on 10/May/18 Answered by ajfour last updated on 10/May/18 $${n}_{\mathrm{1}} +{n}_{\mathrm{2}} ={n} \\ $$$$\left({P}_{\mathrm{0}} +\frac{\mathrm{4}{S}}{{r}_{\mathrm{1}} }\right){r}_{\mathrm{1}} ^{\mathrm{3}} +\left({P}_{\mathrm{0}}…
Question Number 34759 by Tinkutara last updated on 10/May/18 Answered by ajfour last updated on 10/May/18 $$\Rightarrow\:\mathrm{4}\pi\rho{Lr}^{\mathrm{2}} {dr}\:\leqslant\:\mathrm{8}\pi{Srdr} \\ $$$${or}\:\:{r}\:\geqslant\:\frac{\mathrm{2}{S}}{\rho{L}}\:\:\:\:\:\:\:\:\left({as}\:\:\:{dr}\:<\:\mathrm{0}\:\right)\:. \\ $$ Commented by Tinkutara…
Question Number 34411 by Tinkutara last updated on 05/May/18 Commented by Tinkutara last updated on 05/May/18 Commented by ajfour last updated on 06/May/18 $${let}\:{length}\:{of}\:{cylinder}\:{be}\:\boldsymbol{{L}}\: \\…
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Question Number 163974 by mathls last updated on 12/Jan/22 $${is}\:{light}\:{a}\:{matter}? \\ $$ Commented by mr W last updated on 12/Jan/22 $$\left.{does}\:{it}\:{matter}\:{if}\:{it}'{s}\:{a}\:{matter}?\::\right) \\ $$ Answered by…
Question Number 32458 by Tinkutara last updated on 25/Mar/18 $${For}\:{the}\:{model}\:{of}\:{a}\:{plane}\:{in}\:{a}\:{wind} \\ $$$${tunnel},\:{turbulence}\:{occurs}\:{at}\:{a}\:…….. \\ $$$${speed}\:{for}\:{turbulence}\:{for}\:{an}\:{actual} \\ $$$${plane}\:\left({greater}/{smaller}\right). \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com