Question Number 28285 by Tinkutara last updated on 23/Jan/18 Commented by Tinkutara last updated on 27/Jan/18 Anyone? Is this in JEE syllabus or not? Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 28177 by Tinkutara last updated on 21/Jan/18 Commented by Tinkutara last updated on 21/Jan/18 4 and 10 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 83307 by ajfour last updated on 29/Feb/20 Commented by mr W last updated on 01/Mar/20 $${at}\:{equilibrium}\:{position}\:{half}\:{of}\:{the} \\ $$$${object}\:{is}\:{submerged},\:{therefore} \\ $$$$\rho=\frac{\mathrm{1}}{\mathrm{2}}\rho_{\mathrm{0}} \\ $$ Commented…
Question Number 77230 by Umar last updated on 04/Jan/20 $$\mathrm{An}\:\mathrm{astromer}\:\mathrm{finds}\:\mathrm{a}\:\mathrm{new}\:\mathrm{absorption}\: \\ $$$$\mathrm{line}\:\mathrm{with}\:\lambda=\mathrm{164}.\mathrm{1nm}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ultraviolet} \\ $$$$\mathrm{region}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sun}'\mathrm{s}\:\mathrm{continuous}\:\mathrm{spectrum}. \\ $$$$\mathrm{He}\:\mathrm{attributes}\:\mathrm{the}\:\mathrm{line}\:\mathrm{to}\:\mathrm{hydrogen}'\mathrm{s}\: \\ $$$$\mathrm{Layman}\:\mathrm{series}.\:\mathrm{Is}\:\mathrm{he}\:\mathrm{right}?\:\mathrm{Justify} \\ $$$$\mathrm{your}\:\mathrm{answer}. \\ $$$$ \\ $$$$\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{help}}. \\…
Question Number 74384 by jagannath19 last updated on 23/Nov/19 Commented by jagannath19 last updated on 23/Nov/19 $${please}\:{explain} \\ $$ Answered by Tanmay chaudhury last updated…
Question Number 139013 by ajfour last updated on 21/Apr/21 Answered by mr W last updated on 21/Apr/21 Commented by mr W last updated on 21/Apr/21…
Question Number 66433 by yyuuuuuuuu last updated on 15/Aug/19 $$\mathrm{A}\:\mathrm{2kg}\:\mathrm{is}\:\mathrm{attached}\:\mathrm{to}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of}\:\mathrm{a}\:\mathrm{vertical}\:\mathrm{wire}\:\mathrm{of}\:\mathrm{length}\:\mathrm{2m}\:\mathrm{with}\:\mathrm{a}\:\mathrm{diameter}\:\mathrm{of}\:\mathrm{0}.\mathrm{64mm}\:\mathrm{and}\:\mathrm{having}\:\mathrm{an}\:\mathrm{extension}\:\mathrm{of}\:\mathrm{0}.\mathrm{60m}.\mathrm{Calculate}\:\mathrm{the}\:\mathrm{tensile}\:\mathrm{strain}\:\mathrm{on}\:\mathrm{the}\:\mathrm{wire}\left(\mathrm{take}\:\mathrm{g}=\mathrm{9}.\mathrm{8}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com