Question Number 194598 by malwan last updated on 10/Jul/23 $${please} \\ $$$${what}\:{is}\:{the}\:{best}\:{android} \\ $$$${apps}\:{to}\:{drow}\:{complex}\: \\ $$$${functions}\:{and}\:{fractals}\:? \\ $$ Commented by TheHoneyCat last updated on 14/Jul/23…
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Question Number 194011 by Spillover last updated on 26/Jun/23 $${Give}\:{formula}\:{of}\:{the}\:{following}\:{complexes} \\ $$$${Compound} \\ $$$$\left({a}\right){Diammine}\:{Silver}\:\left({i}\right)\:{Chloride} \\ $$$$ \\ $$$$\left({b}\right){Dichloro}\:{aqua}\:{tetra}\:{ammine}\:{Cobalt}\left({iii}\right)\:{Chloride} \\ $$$$ \\ $$$$\left({c}\right){Tetra}\:{ammine}\:\left({ii}\right)\:{hexachloro}\:{platinum}\:\left({iv}\right) \\ $$$$ \\…
Question Number 193953 by Spillover last updated on 24/Jun/23 $${Name}\:{thefollowing}\:{Complex}\:{compound} \\ $$$$\left({a}\right)\left[{Zn}\left({en}\right)_{\mathrm{2}} \left({c}_{\mathrm{2}} {o}_{\mathrm{2}} \right){Br}_{\mathrm{2}} {F}\right]^{−\mathrm{5}} \\ $$$$\left.\left({b}\right){Ni}\left({CN}\right)_{\mathrm{2}} \left({OH}\right)_{\mathrm{3}} {Cl}\right]\:\:\left[{Fe}\left({H}_{\mathrm{2}} {O}\right)_{\mathrm{3}} \left({OH}\right)_{\mathrm{2}} {F}_{\mathrm{2}} {Br}\right] \\…
Question Number 193759 by Mastermind last updated on 19/Jun/23 $$\mathrm{Ques}.\:\mathrm{5}\: \\ $$$$\:\:\:\:\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:\mathrm{a},\mathrm{b}\:\mathrm{are}\:\mathrm{any}\:\mathrm{elements}\:\mathrm{of}\:\:\mathrm{a}\: \\ $$$$\mathrm{group}\:\left(\mathrm{G},\:\ast\right),\:\mathrm{then}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{y}\ast\mathrm{a}=\mathrm{b} \\ $$$$\mathrm{has}\:\mathrm{a}\:\mathrm{unique}\:\mathrm{solution}\:\mathrm{in}\:\left(\mathrm{G},\:\ast\right). \\ $$$$ \\ $$$$\mathrm{Ques}.\:\mathrm{6}\: \\ $$$$\left.\:\:\:\:\:\mathrm{a}\right)\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{set}\:\mathrm{G}\:\mathrm{of}\:\mathrm{all}\:\mathrm{non}-\mathrm{zero}\: \\ $$$$\mathrm{complex}\:\mathrm{numbers},\:\mathrm{is}\:\mathrm{a}\:\mathrm{group}\:\mathrm{under} \\…
Question Number 25075 by Mr easy last updated on 03/Dec/17 $$\mathrm{Let}\:{z}_{\mathrm{1}} \mathrm{and}\:{z}_{\mathrm{2}} \:\mathrm{be}\:\mathrm{two}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$${z}^{\mathrm{2}} +{az}+{b}=\mathrm{0},\:{z}\:\mathrm{being}\:\mathrm{complex}.\:\mathrm{Further} \\ $$$$\mathrm{assume}\:\mathrm{that}\:\mathrm{the}\:\mathrm{origin},\:{z}_{\mathrm{1}} \:\mathrm{and}\:{z}_{\mathrm{2}} \:\mathrm{form} \\ $$$$\mathrm{an}\:\mathrm{equilateral}\:\mathrm{triangle}.\:\mathrm{Then}, \\ $$ Answered…
Complex Numbers Imaginary Unit The imaginary unit, denoted by the symbol $i$ is a mathematical concept that is used to extend the number system to…
Question Number 130818 by Study last updated on 29/Jan/21 $${if}\:\mid{z}_{\mathrm{1}} \mid=\mid{z}_{\mathrm{2}} \mid=\mid{z}_{\mathrm{3}} \mid=\mathrm{1}\:\: \\ $$$${and}\:\:\:\mid\frac{\mathrm{1}}{{z}_{\mathrm{1}} }\mid+\mid\frac{\mathrm{1}}{{z}_{\mathrm{2}} }\mid+\mid\frac{\mathrm{1}}{{z}_{\mathrm{3}} }\mid=\mathrm{1} \\ $$$$\:{find}\:\mid{z}_{\mathrm{1}} +{z}_{\mathrm{2}} +{z}_{\mathrm{3}} \mid=?\:\:\: \\ $$$${z}_{\mathrm{1}}…
Question Number 130639 by mohammad17 last updated on 27/Jan/21 $${for}\:{any}\:{two}\:{complex}\:{number}\:\left({z},{w}\right)\:{then} \\ $$$$\sqrt{{z}.{w}}=\sqrt{{z}}.\sqrt{{w}} \\ $$$$ \\ $$$${true}\:\:{or}\:{false} \\ $$ Commented by malwan last updated on 27/Jan/21…
Question Number 130102 by mohammad17 last updated on 22/Jan/21 $${if}\:{U}\left({x},{y}\right)=\mathrm{2}{x}−{x}^{\mathrm{3}} +\mathrm{3}{xy}^{\mathrm{2}} \:{construct}\:{a}\:{complex}\: \\ $$$${analytical}\:{function},\:{the}\:{expression} \\ $$$${of}\:{which}\:{is}\:{the}\:{true}\:{part}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129688 by Engr_Jidda last updated on 17/Jan/21 $${complex}\:{analysis} \\ $$$$\oint_{{C}} \frac{\varrho^{\mathrm{2}{z}} +{sinz}^{\mathrm{2}} }{\left({z}−\mathrm{2}\right)\left({z}−\mathrm{3}\right)}{dz}\:\:\:{C}:\mid{Z}\mid=\mathrm{5} \\ $$ Answered by mathmax by abdo last updated on…