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Question Number 216486 by Tawa11 last updated on 08/Feb/25

∫_( 0) ^( 1)  x(√(x  ((x  ((x  ((x ...))^(1/5) ))^(1/4) ))^(1/3) ))  dx

01xxxxx...543dx

Answered by mehdee7396 last updated on 09/Feb/25

x×x^(1/2) ×x^(1/6) ×x^(1/(24)) ×x^(1/(120)) ×...  =x^(Σ_1 ^∞ (1/(n!)).) =x^(e−1)   ⇒I=∫_0 ^1 x^(e−1) dx=(1/(e−1))(x^(e−1) )]_0 ^1   =(1/(e−1))

x×x12×x16×x124×x1120×...=x11n!.=xe1I=01xe1dx=1e1(xe1)]01=1e1

Commented by Tawa11 last updated on 09/Feb/25

Thanks sir.

Thankssir.

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