All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 216486 by Tawa11 last updated on 08/Feb/25
∫01xxxxx...543dx
Answered by mehdee7396 last updated on 09/Feb/25
x×x12×x16×x124×x1120×...=x∑∞11n!.=xe−1⇒I=∫01xe−1dx=1e−1(xe−1)]01=1e−1
Commented by Tawa11 last updated on 09/Feb/25
Thankssir.
Terms of Service
Privacy Policy
Contact: info@tinkutara.com