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Question Number 203490 by cortano12 last updated on 20/Jan/24
1×3×5×7×9×...×2005=...(mod1000)
Answered by deleteduser1 last updated on 20/Jan/24
x=1×3×5...×2005≡0(mod125)x≡(1×3×5×7)250×1×3×5(mod8)≡7(mod8)x=125q≡7(mod8)⇒5q≡15(mod8)⇒q≡3(mod8)1×3×5...×2005=125(8k+3)≡375(mod1000)
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