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Question Number 156495 by chusrang last updated on 11/Oct/21

$$1.\mathrm{Write}\mathrm{the}\mathrm{first}\mathrm{three}\mathrm{terms}\mathrm{of}\mathrm{each}\mathrm{of}\mathrm{the}\mathrm{following}\mathrm{sequences}:$$$$\left(\mathrm{a}\right){\mathrm{a}}_n=\frac{3^n}{2^n+1}\left(\mathrm{b}\right){\mathrm{a}}_n={(-1)}^{n-1}{n}^3$$

Answered by Rasheed.Sindhi last updated on 11/Oct/21

$$\left(\mathrm{a}\right)\frac{3^1}{2^1+1},\frac{3^2}{2^2+1},\frac{3^3}{2^3+1}$$$$\frac{3}{2+1},\frac{9}{4+1},\frac{27}{8+1}$$$$\frac{3}{3},\frac{9}{5},\frac{27}{9}$$$$1,\frac{9}{5},3$$$$\left(\mathrm{b}\right){(-1)}^{1-1}{\left(1\right)}^3,{(-1)}^{2-1}{\left(2\right)}^3,{(-1)}^{3-1}{\left(3\right)}^3$$$${(-1)}^0\left(1\right),(-1)\left(8\right),{(-1)}^2\left(27\right)$$$$1,-8,27$$

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