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Question Number 161234 by mathlove last updated on 14/Dec/21
1:!x=?2:!!x=?3:x!!=?whenXisodd4:x!!=?whenXisevan5:x!!!=?whenXisodd6:x!!!=?whenXisevan
Commented by mr W last updated on 14/Dec/21
!xisdefinedasnumberofderangements.ithink!!xisnotdefined.youcouldmean!(!x).x!!isdefinedasx×(x−2)×(x−4)×...×k(k⩾1)similarlyyoucoulddefinex!!!asx!!!=x×(x−3)×(x−6)×...×k(k⩾1)
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