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Question Number 100000 by Dwaipayan Shikari last updated on 24/Jun/20

$$1+\frac{1}{32}+\frac{1}{243}+\frac{1}{1024}+...\mathrm{\infty }$$

Commented by ajfour last updated on 27/Jun/20

$$thisquestionnumberisa$$$$landmark,congratulations$$$$toallofusrelatedwiththis$$$$forum!$$

Answered by maths mind last updated on 24/Jun/20

$$=\sum _{n\in {\mathbb{N}}^{\ast }}\frac{1}{n^5}=\zeta \left(5\right)$$

Answered by smridha last updated on 24/Jun/20

$$\mathit{\zeta }\left(5\right)\approx 1.03692.......$$

Commented by Rio Michael last updated on 24/Jun/20

$$\mathrm{sir}\mathrm{how}\mathrm{do}\mathrm{you}\mathrm{get}\mathrm{this}\mathrm{approximate}?$$

Commented by smridha last updated on 24/Jun/20

$$\mathit{i}\mathit{j}\mathit{u}\mathit{s}\mathit{t}\mathit{p}\mathit{u}\mathit{t}\mathit{i}\mathit{t}\mathit{f}\mathit{r}\mathit{o}\mathit{m}\mathit{t}\mathit{a}\mathit{b}\mathit{l}\mathit{e}...$$$$\mathit{I}\mathit{k}\mathit{n}\mathit{o}\mathit{w}\mathit{a}\mathit{l}\mathit{l}\mathit{t}\mathit{h}\mathit{e}\mathit{c}\mathit{a}\mathit{l}\mathit{c}\mathit{u}\mathit{l}\mathit{a}\mathit{t}\mathit{i}\mathit{o}\mathit{n}\mathit{s}\mathit{b}\mathit{u}\mathit{t}$$$${\mathit{i}\mathit{t}}^{\prime }s\mathit{t}\mathit{o}\mathit{o}\mathit{l}\mathit{e}\mathit{n}\mathit{g}\mathit{t}\mathit{h}\mathit{y}...\mathit{m}\mathit{o}\mathit{s}\mathit{t}\mathit{l}\mathit{y}\mathit{f}\mathit{o}\mathit{r}$$$$\mathit{\zeta }(2\mathit{n}+1)\mathit{w}\mathit{h}\mathit{e}\mathit{r}\mathit{e}\mathit{n}=1,2,3......$$

Commented by Rio Michael last updated on 24/Jun/20

$$\mathrm{well}\mathrm{thank}\mathrm{you}\mathrm{sir}.\mathrm{i}\mathrm{will}\mathrm{compute}$$$$\mathrm{that}.$$

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