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Question Number 100036 by bobhans last updated on 24/Jun/20
f(x)=1+sin2x−1−2sinxxg(x)=2x+2x.findlimx→0g(f(x))
Answered by john santu last updated on 24/Jun/20
limx→0g(f(x))=g(limx→0f(x))=g(limx→01+sin2x−1−2sinxx)=g(limx→0(1+sin2x2)−(1−2sinx2)x)=g(limx→012sin2x+sinxx)=g(2)=2.2+2.2=4+2=6◼
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