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Question Number 100191 by bobhans last updated on 25/Jun/20

$$\int x^2{e}^{x}dx?$$

Commented by bobhans last updated on 25/Jun/20

$$\mathrm{D}.\mathrm{I}\mathrm{method}\Rightarrow x^2{e}^x-2{xe}^x+2e^x+C$$$$\mathrm{D}\mathrm{I}$$$$x^2(+)e^x$$$$2(-)e^x$$$$2(+)e^x$$$$0(-)e^x$$

Answered by Dwaipayan Shikari last updated on 25/Jun/20

$$=x^2\int e^x-\int 2{xe}^x=x^2{e}^x-2{xe}^x+2e^x+\mathrm{Constant}$$$$$$

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