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Question Number 100491 by bobhans last updated on 27/Jun/20

Answered by bramlex last updated on 27/Jun/20

$$let\mathrm{arccot}\frac{1}{2}=z\Rightarrow \cot z=\frac{1}{2}$$$$let\mathrm{arccot}\frac{2}{3}=w\Rightarrow \cot w=\frac{2}{3}$$$$\iff \tan (z+w)=\frac{\tan z+\tan w}{1-\tan z.\tan w}$$$$=\frac{2+\frac{3}{2}}{1-2.\frac{3}{2}}=\frac{7}{2-6}=-\frac{7}{4}◼$$

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