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Question Number 100684 by bemath last updated on 28/Jun/20
(x2+xy)dydx=xy+y2
Answered by bobhans last updated on 28/Jun/20
sety=sx⇒dydx=s+xdsdx(x2+x2s)(s+xdsdx)=x2s+x2s2(1+s)(s+xdsdx)=s(s+1)s+xdsdx=s⇒xdsdx=0dsdx=0⇒s=0+C;yx=C,x≠0y=Cx
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