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Question Number 100792 by bramlex last updated on 28/Jun/20

Answered by bobhans last updated on 28/Jun/20

((x+xy)/y) = ((y+xy)/x) ⇒ x^2 +x^2 y = y^2 +xy^2 x^2 −y^2 = xy^2 −x^2 y ; (x−y)(x+y)=−xy(x−y) ⇒ x+y = −xy . Then (1/x) + (1/y) = ((x+y)/(xy)) = −1 ★

x+xyy=y+xyx⇒x2+x2y=y2+xy2x2−y2=xy2−x2y;(x−y)(x+y)=−xy(x−y)⇒x+y=−xy.Then1x+1y=x+yxy=−1★

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