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Question Number 100793 by bramlex last updated on 28/Jun/20

Commented by bobhans last updated on 28/Jun/20

$$\mathrm{The}\mathrm{perimeter}\mathrm{of}\mathrm{isosceles}\mathrm{\Delta }\mathrm{MBC}=5+5+6=16$$

Answered by Dwaipayan Shikari last updated on 28/Jun/20

$$radiusofcircle=3unit$$$$so\sqrt{{(7-3)}^2+3^2}=5unit$$$$perimetreof△\mathrm{BMC}=5+5+6=16unit$$

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