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Question Number 100866 by mathmax by abdo last updated on 29/Jun/20
solve3x2y″−2xy′+4y=0
Answered by bramlex last updated on 29/Jun/20
lety=xrissolution.y′=rxr−1,y″=r(r−1)xr−2⇔3x2.{r(r−1)xr−2}−2x(rxr−1)+4xr=0(3r2−3r)xr−2rxr+4xr=0⇔3r2−5r+4=0r=5±25−486=5±i236r=56±i236∵y={x56+i236x56−i236
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