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Question Number 100870 by bramlex last updated on 29/Jun/20
Commented by bemath last updated on 29/Jun/20
π−e=0.4233(π−e)ln(1−2cos2x)⩾(π−e)0case(1)⇒ln(1−2(12+12cos2x))⩽0ln(−cos2x)⩽0⇒−cos2x⩽1cos2x⩾−1,∀x∈Rcase(2)⇒−cos2x>0;cos2x<0π4<x<3π4⇒x∈(π4,3π4)★
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