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Question Number 100960 by john santu last updated on 29/Jun/20

$$\{\begin{array}{l}\sqrt{x^2-6x+9}=3-x\\ \sqrt{x^2+6x+9}=x+3\end{array}$$

Commented by bobhans last updated on 29/Jun/20

$$\sqrt{{\mathrm{x}}^2-6\mathrm{x}+9}=\mid \mathrm{x}-3\mid =3-\mathrm{x}\to \mathrm{x}⩽3$$$$\sqrt{{\mathrm{x}}^2+6\mathrm{x}+9}=\mid \mathrm{x}+3\mid =\mathrm{x}+3\to \mathrm{x}⩾-3$$$$\mathrm{so}-3⩽x⩽3$$

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