find the equation of circle whose parametric form is given by x=3cos θ+5 and y= 3sin θ−7 and second part is x=4cos θ−3 and y=4sin θ+4. find centre and radius of above circle. guys plz ans. me soon.....


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Question Number 1012 by rpatle69@gmail.com last updated on 13/May/15

$f i n d t h e e q u a t i o n o f c i r c l e w h o s e$ $p a r a m e t r i c f o r m i s g i v e n b y$ $x = 3 \cos θ + 5 a n d y = 3 \sin θ - 7 a n d$ $s e c o n d p a r t i s x = 4 \cos θ - 3 a n d$ $y = 4 \sin θ + 4 . f i n d c e n t r e a n d$ $r a d i u s o f a b o v e c i r c l e .$ $g u y s p l z a n s . m e s o o n . . . . .$
	Answered by sudhanshur last updated on 13/May/15

	$x - 5 = 3 \cos θ$ $y + 7 = 3 \sin θ$ $s q u a r e a n d a d d$ ${(x - 5)}^{2} + {(y + 7)}^{2} = 9$
	Answered by sudhanshur last updated on 13/May/15

	$x + 3 = 4 \cos θ$ $y - 4 = 4 \sin θ$ ${(x + 3)}^{2} + {(y - 4)}^{2} = 16$
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