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Question Number 101362 by bobhans last updated on 02/Jul/20
Commented by bemath last updated on 02/Jul/20
(x2+3y2)dx+(2xy−x)dy=0M=x2+3y2→∂M∂y=6yN=2xy−x→∂N∂x=2y−1∂M∂y≠∂N∂x⇐nonexact
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