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Question Number 101373 by Dwaipayan Shikari last updated on 02/Jul/20
limn→∞∑4nr=1nr(3r+4n)2
Commented by Dwaipayan Shikari last updated on 02/Jul/20
1nlimn→∞∑4nr=1(nr)32.1(3+4nr)2=∫041x32.1(3+4x12)2dx=∫041x32(3+4x12)2dx−12∫04−2x32(3+4x12)2dx=−12∫∞5dtt2=12[1t]∞5=110Isitright???????
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