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Question Number 101393 by bemath last updated on 02/Jul/20

Answered by 1549442205 last updated on 02/Jul/20

Suppose the number of cars manufactured  in the first yeat be n units .Then in the second year  is ((3n)/2) and in the third year is 2n .Sum of cars  manufactured in the 3_years period is  ((9n)/(2 )).Hence P=(((3n)/2)/((9n)/2))=(1/3)⇒Choose A

$$\mathrm{Suppose}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{cars}\:\mathrm{manufactured} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{first}\:\mathrm{yeat}\:\mathrm{be}\:\mathrm{n}\:\mathrm{units}\:.\mathrm{Then}\:\mathrm{in}\:\mathrm{the}\:\mathrm{second}\:\mathrm{year} \\ $$$$\mathrm{is}\:\frac{\mathrm{3n}}{\mathrm{2}}\:\mathrm{and}\:\mathrm{in}\:\mathrm{the}\:\mathrm{third}\:\mathrm{year}\:\mathrm{is}\:\mathrm{2n}\:.\mathrm{Sum}\:\mathrm{of}\:\mathrm{cars} \\ $$$$\mathrm{manufactured}\:\mathrm{in}\:\mathrm{the}\:\mathrm{3\_years}\:\mathrm{period}\:\mathrm{is} \\ $$$$\frac{\mathrm{9}\boldsymbol{\mathrm{n}}}{\mathrm{2}\:}.\boldsymbol{\mathrm{Hence}}\:\boldsymbol{\mathrm{P}}=\frac{\frac{\mathrm{3}\boldsymbol{\mathrm{n}}}{\mathrm{2}}}{\frac{\mathrm{9}\boldsymbol{\mathrm{n}}}{\mathrm{2}}}=\frac{\mathrm{1}}{\mathrm{3}}\Rightarrow\boldsymbol{\mathrm{Choose}}\:\boldsymbol{\mathrm{A}} \\ $$$$ \\ $$

Commented by bemath last updated on 02/Jul/20

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

Commented by 1549442205 last updated on 02/Jul/20

You are welcome sir.

$$\mathrm{You}\:\mathrm{are}\:\mathrm{welcome}\:\mathrm{sir}. \\ $$

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