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Question Number 101558 by mhmd last updated on 03/Jul/20
ify=sin2xisthesolutionofdifferintialequationd2ydx2+4y=kthenthekis.......
Answered by bemath last updated on 03/Jul/20
y′=2cos2x⇒y″=−4sin2xy″+4y=−4sin2x+4sin2x=0=k★
Commented by mhmd last updated on 03/Jul/20
thankyousir
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