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Question Number 101568 by Quvonchbek last updated on 03/Jul/20

Answered by mr W last updated on 03/Jul/20

$$x^{25}\times \frac{(1+3)(1+3^2)...(1+3^{25})}{3^{1+2+...+25}}=1$$$$x^{25}\times \frac{(1+3)(1+3^2)...(1+3^{25})}{3^{13\times 25}}=1$$$$\Rightarrow x=\frac{3^{13}}{\sqrt[25]{(1+3)(1+3^2)...(1+3^{25})}}$$

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