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Question Number 102002 by Jamshidbek2311 last updated on 06/Jul/20

Commented by mr W last updated on 06/Jul/20

$$please{don}^{\prime }tpostthesamequestion$$$$againandagain.ifyouhavedoubt,$$$$givecommentintheoldthread,{don}^{\prime }t$$$$openanewthread.$$

Commented by mr W last updated on 06/Jul/20

Commented by 1549442205 last updated on 06/Jul/20

$$\mathrm{I}\mathrm{guess}\mathrm{he}\left(\mathrm{she}\right)\mathrm{want}\mathrm{the}\mathrm{solvers}\mathrm{give}\mathrm{him}$$$$\left(\mathrm{her}\right)\mathrm{a}\mathrm{particilar}\mathrm{result}\mathrm{with}\mathrm{true}\mathrm{number}\mathrm{which}$$$$\mathrm{was}\mathrm{reduced}$$

Commented by Jamshidbek2311 last updated on 06/Jul/20

$$ok.sorry$$

Commented by 06122004 last updated on 06/Jul/20

$$\mathrm{S}=\frac{3^1+1}{3^1}\cdot \frac{3^2+1}{3^2}\cdot \frac{3^3+1}{3^3}\cdot ...\cdot \frac{3^{25}+1}{3^{25}}=$$$$=\underset{\mathrm{n}=1}{\prod ^{25}}\frac{3^{\mathrm{n}}+1}{3^{\mathrm{n}}}▴$$

Commented by prakash jain last updated on 06/Jul/20

$$\mathrm{Is}\mathrm{it}\mathrm{possible}\mathrm{to}\mathrm{calculate}\mathrm{a}\mathrm{closed}$$$$\mathrm{form}\mathrm{product}\mathrm{value}\mathrm{without}$$$$\mathrm{actual}\mathrm{calculation}?$$$$\mathrm{I}\mathrm{thought}\mathrm{about}\mathrm{it}\mathrm{for}\mathrm{a}\mathrm{long}$$$$\mathrm{time}\mathrm{but}\mathrm{could}\mathrm{not}\mathrm{find}\mathrm{a}\mathrm{way}.$$$$\mathrm{I}\mathrm{will}\mathrm{need}\mathrm{to}\mathrm{read}\mathrm{a}\mathrm{little}\mathrm{bit}\mathrm{more}.$$

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