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Question Number 10250 by jaikar last updated on 31/Jan/17

Commented by jaikar last updated on 31/Jan/17

please Q no. 10

$${please}\:{Q}\:{no}.\:\mathrm{10} \\ $$$$ \\ $$

Answered by ridwan balatif last updated on 31/Jan/17

10. n=1.5625×10^(18) electron, 1 electron has ≈ 1.6×10^(−19) C  Q/t=n.e/1s           =1.5625×10^(18) ×1.6×10^(−19)            =2.5×10^(−1) C/s  t  =((12C)/(2.5×10^(−1) C/s))=48s   Answer: C

$$\mathrm{10}.\:\mathrm{n}=\mathrm{1}.\mathrm{5625}×\mathrm{10}^{\mathrm{18}} \mathrm{electron},\:\mathrm{1}\:\mathrm{electron}\:\mathrm{has}\:\approx\:\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} \mathrm{C} \\ $$$$\mathrm{Q}/\mathrm{t}=\mathrm{n}.\mathrm{e}/\mathrm{1s} \\ $$$$\:\:\:\:\:\:\:\:\:=\mathrm{1}.\mathrm{5625}×\mathrm{10}^{\mathrm{18}} ×\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} \\ $$$$\:\:\:\:\:\:\:\:\:=\mathrm{2}.\mathrm{5}×\mathrm{10}^{−\mathrm{1}} \mathrm{C}/\mathrm{s} \\ $$$$\mathrm{t}\:\:=\frac{\mathrm{12C}}{\mathrm{2}.\mathrm{5}×\mathrm{10}^{−\mathrm{1}} \mathrm{C}/\mathrm{s}}=\mathrm{48s}\: \\ $$$$\mathrm{Answer}:\:\mathrm{C} \\ $$

Commented by jaikar last updated on 31/Jan/17

thanks

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