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Question Number 102553 by aurpeyz last updated on 09/Jul/20

Commented by aurpeyz last updated on 09/Jul/20

$$\mathrm{pls}\mathrm{help}$$

Commented by aurpeyz last updated on 09/Jul/20

Commented by Rio Michael last updated on 10/Jul/20

$$\mathrm{Force}=\mu F_N+\mathrm{mg}\sin \theta$$$$\Rightarrow F=(0.4)(10\times 9.8)N+\left(10\right)(9.8)\sin 60N$$

Answered by mr W last updated on 10/Jul/20

$$F\cos \theta -mg\sin \theta ⩾\mu (mg\cos \theta +F\sin \theta )$$$$F(\cos \theta -\mu \sin \theta )⩾mg(\mu \cos \theta +\sin \theta )$$$$\Rightarrow F⩾\frac{mg(\mu \cos \theta +\sin \theta )}{\cos \theta -\mu \sin \theta }$$$$\Rightarrow F⩾\frac{mg(\mu +\tan \theta )}{1-\mu \tan \theta }$$$$\Rightarrow F⩾\frac{10\times 9.81(0.4+\sqrt{3})}{1-0.4\times \sqrt{3}}=681N$$

Commented by aurpeyz last updated on 10/Jul/20

$$\mathrm{your}\mathrm{solution}\mathrm{is}\mathrm{great}\mathrm{Sir}.\mathrm{pls}\mathrm{explain}\mathrm{the}\mathrm{first}\mathrm{line}\mathrm{of}\mathrm{the}\mathrm{solution}.\mathrm{i}\mathrm{will}\mathrm{understand}\mathrm{the}\mathrm{rest}$$

Commented by aurpeyz last updated on 10/Jul/20

$$\mathrm{with}\mathrm{this}\mathrm{solution}\mathrm{it}\mathrm{seem}\mathrm{like}\mathrm{there}\mathrm{is}\mathrm{a}\mathrm{force}\mathrm{action}\mathrm{at}\mathrm{\Theta }\mathrm{degrees}\mathrm{to}\mathrm{the}\mathrm{plane}$$

Commented by mr W last updated on 10/Jul/20

Commented by aurpeyz last updated on 10/Jul/20

$$\mathrm{where}\mathrm{F}\mathrm{is}\mathrm{the}\mathrm{horizontal}\mathrm{force}\mathrm{right}?\mathrm{so}\mathrm{i}\mathrm{will}\mathrm{just}\mathrm{have}\mathrm{to}\mathrm{resolve}\mathrm{to}\mathrm{get}\mathrm{the}\mathrm{answers}\mathrm{like}\mathrm{hou}\mathrm{did}$$

Commented by aurpeyz last updated on 10/Jul/20

$$\mathrm{Sir}\mathrm{Pls}\mathrm{check}\mathrm{Q}.102194.\mathrm{what}\mathrm{will}\mathrm{be}\mathrm{the}\mathrm{direction}\mathrm{of}\mathrm{the}\mathrm{friction}?$$

Commented by mr W last updated on 10/Jul/20

$$inthisquestionyoushouldmove$$$$theobjectuptotheplaneandthe$$$$frictionisalwaysintheopposite$$$$directiontothemovementtheobject$$$$triestomake.inthiscaseitis$$$$downwards.$$$$butinQ102194you{don}^{\prime }tneedtomove$$$$uptheobject,youjustneedto$$$$preventittomovedown,inthatcase$$$$thefrictionisupwards,becausethe$$$$objecttriestomovedownwards.$$

Commented by aurpeyz last updated on 10/Jul/20

$$\mathrm{i}\mathrm{understand}\mathrm{you}\mathrm{Sir}.\mathrm{thanks}\mathrm{alot}.$$

Commented by aurpeyz last updated on 11/Jul/20

$$\mathrm{Sir}\mathrm{cam}\mathrm{you}\mathrm{recomend}\mathrm{a}\mathrm{textbook}\mathrm{for}\mathrm{me}\mathrm{Sir}.\mathrm{that}\mathrm{will}\mathrm{help}\mathrm{me}\mathrm{with}\mathrm{all}\mathrm{of}\mathrm{this}?$$

Commented by mr W last updated on 11/Jul/20

$$nosir.notbecausei{don}^{\prime }twanttotell$$$$you,butbecausei{don}^{\prime }tknowsucha$$$$book,notbecausei{don}^{\prime }tfindthe$$$$booksgoodenough,butbecauseihave$$$$neverreadsuchabooksinceileft$$$$theschool.$$

Commented by aurpeyz last updated on 11/Jul/20

$$\mathrm{okay}\mathrm{Sir}$$

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